SQL Count 使用来自连接的信息

Question

我需要计算每个站点编号和每个订单模式出现的 InternalMenuLinkItemNumber 次数。然后我需要显示 MenuItemID 并使用项目编号通过内部连接来执行此操作，但是当我添加此连接时，它会扭曲 QTY 结果。我试过在 COUNT 中使用 distinct，但所有的 QTY 都是 1。请协助。

QTY 结果 100% 正确但没有 MenuItemID 的查询和结果。

 SELECT ST_Sites.BusinessUnit,[ST_SalesMixTransactions_RealTimeFeed].SiteNumber,InternalMenuLinkItemNumber,[ST_SalesMix].MenuItemID,OrderMode,SellingPrice,COUNT(ST_SalesMixTransactions_RealTimeFeed.InternalMenuLinkItemNumber) as QTY 

FROM ST_AlohaSalesMixTransactions_RealTimeFeed

inner join ST_Sites on ST_Sites.SiteNumber= [ST_SalesMixTransactions_RealTimeFeed].SiteNumber 

where [ST_SalesMixTransactions_RealTimeFeed].BusinessDate between'2017-06-27'and'2017-07-03' and [ST_SalesMixTransactions_RealTimeFeed].SiteNumber = '1001006'

group by InternalMenuLinkItemNumber,[ST_SalesMixTransactions_RealTimeFeed].SiteNumber,OrderMode,SellingPrice,ST_Sites.BusinessUnit,[ST_SalesMix].MenuItemID

order by InternalMenuLinkItemNumber 

QTY 符合预期的结果：

如果我添加内部连接来获取 MenuItemID： 查询：

SELECT ST_Sites.BusinessUnit,[ST_SalesMixTransactions_RealTimeFeed].SiteNumber,InternalMenuLinkItemNumber,[ST_SalesMix].MenuItemID,OrderMode,SellingPrice,COUNT(ST_SalesMixTransactions_RealTimeFeed.InternalMenuLinkItemNumber) as QTY 

FROM ST_AlohaSalesMixTransactions_RealTimeFeed

inner join ST_SalesMix on [ST_AlohaSalesMixTransactions_RealTimeFeed].InternalMenuLinkItemNumber= ST_SalesMix.ItemNumber

inner join ST_Sites on ST_Sites.SiteNumber= [ST_SalesMixTransactions_RealTimeFeed].SiteNumber 

where [ST_SalesMixTransactions_RealTimeFeed].BusinessDate between'2017-06-27'and'2017-07-03' and [ST_SalesMixTransactions_RealTimeFeed].SiteNumber = '1001006'

group by InternalMenuLinkItemNumber,[ST_SalesMixTransactions_RealTimeFeed].SiteNumber,OrderMode,SellingPrice,ST_Sites.BusinessUnit,[ST_SalesMix].MenuItemID

order by InternalMenuLinkItemNumber

QTY 现在偏离的结果：

如果我使用不同的： 查询：

SELECT ST_Sites.BusinessUnit,[ST_SalesMixTransactions_RealTimeFeed].SiteNumber,InternalMenuLinkItemNumber,[ST_SalesMix].MenuItemID,OrderMode,SellingPrice,COUNT(distinct ST_SalesMixTransactions_RealTimeFeed.InternalMenuLinkItemNumber) as QTY 

FROM ST_AlohaSalesMixTransactions_RealTimeFeed

inner join ST_SalesMix on [ST_AlohaSalesMixTransactions_RealTimeFeed].InternalMenuLinkItemNumber= ST_SalesMix.ItemNumber

inner join ST_Sites on ST_Sites.SiteNumber= [ST_SalesMixTransactions_RealTimeFeed].SiteNumber 

where [ST_SalesMixTransactions_RealTimeFeed].BusinessDate between'2017-06-27'and'2017-07-03' and [ST_SalesMixTransactions_RealTimeFeed].SiteNumber = '1001006'

group by InternalMenuLinkItemNumber,[ST_SalesMixTransactions_RealTimeFeed].SiteNumber,OrderMode,SellingPrice,ST_Sites.BusinessUnit,[ST_SalesMix].MenuItemID

order by InternalMenuLinkItemNumber

QTY 的结果现在全为 1：

Answer 1

如果我理解正确，你想要类似的东西

SELECT SiteNumber, OrderMode, count([DISTINCT?] InternalMenuLinkItemNumber)
...
GROUP BY SiteNumber, OrderMode

您要计算 InternalMenuLinkItemNumber，因此 InternalMenuLinkItemNumber 不能出现在 GROUP BY 子句中。

编辑： 使用 GROUP BY 时，SELECT 列表只能包含在 GROUP BY 子句中也提到的列，或聚合函数（在任意列上）。

Answer 2

试试这个：

SELECT a.InternalMenuLinkItemNumber, a.SiteNumber, a.OrderMode, a.SellingPrice, a.BusinessUnit, a.MenuItemID, a.QTY, CASE WHEN MAX(b.MenuItemID) = MIN(b.MenuItemID) THEN MAX(b.MenuItemID) ELSE -1 END AS MenuItemID
    FROM
        (SELECT ST_Sites.BusinessUnit, [ST_SalesMixTransactions_RealTimeFeed].SiteNumber, InternalMenuLinkItemNumber, [ST_SalesMix].MenuItemID, OrderMode, SellingPrice, COUNT(ST_SalesMixTransactions_RealTimeFeed.InternalMenuLinkItemNumber) as QTY 
            FROM ST_AlohaSalesMixTransactions_RealTimeFeed
            INNER JOIN ST_Sites on ST_Sites.SiteNumber = [ST_SalesMixTransactions_RealTimeFeed].SiteNumber 
            WHERE [ST_SalesMixTransactions_RealTimeFeed].BusinessDate between'2017-06-27'and'2017-07-03' and [ST_SalesMixTransactions_RealTimeFeed].SiteNumber = '1001006'
            GROUP BY InternalMenuLinkItemNumber, [ST_SalesMixTransactions_RealTimeFeed].SiteNumber, OrderMode, SellingPrice, ST_Sites.BusinessUnit, [ST_SalesMix].MenuItemID
         ) a
    INNER JOIN ST_SalesMix b ON a.InternalMenuLinkItemNumber = b.ItemNumber
    GROUP BY a.InternalMenuLinkItemNumber, a.SiteNumber, a.OrderMode, a.SellingPrice, a.BusinessUnit, a.MenuItemID, a.QTY
    ORDER BY a.InternalMenuLinkItemNumber

它的原理是您的第一个查询给出了很好的计数，因此请保持原样（现在是内部查询），然后在它之外进行有问题的联接。显然，ST_SalesMix 对于第一个查询中的每个正确计数的行都有很多行，所以我在原始组列表上进行分组，但这意味着您可能会获得多个 MenuItemID。我正在通过测试 MAX 和 MIN MenuItemIDs 在 CASE 语句中检查这一点 - 如果它们相同，则返回 MAX(MenuItemID) 否则我将返回 -1 作为错误标志，以指示有多个 MenuItemIDs 与此组相关联.这可能不是最有效的方法，但我没有太多工作要做。

我希望这会有所帮助。

Answer 3

现在全部排序。谢谢大家。 @jwolf 你建议的查询就是答案。