使用一个表中的整数值在另一个 SQL 表中查找值答案

【问题标题】：use integer values in one table to look up values in another SQL table使用一个表中的整数值在另一个 SQL 表中查找值
【发布时间】：2020-06-25 18:09:13
【问题描述】：

我希望在一个表中使用整数值来查找另一个 SQL 表中的字符串值。例如，我有两个表：

╔═════════╦═══════════╦═════════════════╦═══════════════════╗
║ CarType ║ CarColour ║ AbnormalCarType ║ AbnormalCarColour ║
╠═════════╬═══════════╬═════════════════╬═══════════════════╣
║       1 ║         1 ║ 1               ║ 2                 ║
║       1 ║         2 ║ null            ║ null              ║
║       2 ║         1 ║ 1               ║ 2                 ║
║       2 ║         2 ║ 1               ║ 1                 ║
╚═════════╩═══════════╩═════════════════╩═══════════════════╝

然后在我的另一个表中：

╔═══════════╦═══════════════╦═════════════╦═════════════════╦══╗
║ CarTypeId ║ CarTypeString ║ CarColourId ║ CarColourString ║  ║
╠═══════════╬═══════════════╬═════════════╬═════════════════╬══╣
║         1 ║ "Hyundai"     ║           1 ║ "Red"           ║  ║
║         1 ║ "Hyundai"     ║           2 ║ "Blue"          ║  ║
║         2 ║ "Toyota"      ║           1 ║ "Green"         ║  ║
║         2 ║ "Toyota"      ║           2 ║ "Yellow"        ║  ║
╚═══════════╩═══════════════╩═════════════╩═════════════════╩══╝

然后为输出

╔═════════╦═══════════╦═════════════════╦═══════════════════╗
║ CarType ║ CarColour ║ AbnormalCarType ║ AbnormalCarColour ║
╠═════════╬═══════════╬═════════════════╬═══════════════════╣
║ Hyundai ║ Red       ║ Hyundai         ║ Blue              ║
║ Hyundai ║ Blue      ║ null            ║ null              ║
║ Toyota  ║ Green     ║ Hyundai         ║ Blue              ║
║ Toyota  ║ Yellow    ║ Hyundai         ║ Red               ║
╚═════════╩═══════════╩═════════════════╩═══════════════════╝

我尝试了双重内连接，第一次是 CarType、CarColour，然后是 AbnormalCarType 和 AbnormalCarColour，但它没有产生我想要的结果。

非常感谢！

【问题讨论】：

标签： mysql sql google-bigquery

【解决方案1】：

以下是 BigQuery 标准 SQL

#standardSQL
SELECT b.CarTypeString AS CarType, b.CarColourString AS CarColour, 
  c.CarTypeString AS AbnormalCarType, c.CarColourString AS AbnormalCarColour
FROM `project.dataset.tableB` b  
LEFT JOIN `project.dataset.tableA` a
ON b.CarTypeId = a.CarType AND b.CarColourId = a.CarColour
LEFT JOIN `project.dataset.tableB` c
ON a.AbnormalCarType = c.CarTypeId AND a.AbnormalCarColour = c.CarColourId

如果适用于您示例中的示例数据

WITH `project.dataset.tableA` AS (
  SELECT 1 CarType, 1 CarColour, 1 AbnormalCarType, 2 AbnormalCarColour UNION ALL
  SELECT 1, 2, NULL, NULL UNION ALL
  SELECT 2, 1, 1, 2 UNION ALL
  SELECT 2, 2, 1, 1 
), `project.dataset.tableB` AS (
  SELECT 1 CarTypeId, 'Hyundai' CarTypeString, 1 CarColourId, 'Red' CarColourString UNION ALL
  SELECT 1, 'Hyundai', 2, 'Blue' UNION ALL
  SELECT 2, 'Toyota', 1, 'Green' UNION ALL
  SELECT 2, 'Toyota', 2, 'Yellow' 
)

输出符合预期

Row CarType CarColour   AbnormalCarType AbnormalCarColour    
1   Hyundai Red         Hyundai         Blue     
2   Hyundai Blue        null            null     
3   Toyota  Green       Hyundai         Blue     
4   Toyota  Yellow      Hyundai         Red

【讨论】：

非常感谢您的回复！不幸的是，我的最小工作示例还不够好，这也不是我想要的。我已经编辑了我的开场白。如果您有时间再看一遍，那就太好了。
顺便说一句，与此同时，我根据您的新样本数据测试了给出的答案（假设 AbnormalCarColour 归档实际上应该是 CarColourString 与原始样本一样）并且它仍然有效。无论如何 - 请考虑上述建议
非常感谢再次回复并为之前道歉，以后发帖时会牢记。