这可能是错误的方向,因为尚不完全清楚您的最终目标是什么,但让我尝试帮助您
不知何故,我觉得您的目标表应如下所示
type metric1 metric2 metric3
1 1271 518 945
1 1287 495 963
所以,我的建议是分两步完成
第 1 步 - 将数据加载为 CSV,仅包含一个字段 - 假设表格 theTable 包含字段 data
data
{"data": {"events": [[1, 1271, 518, 945], [1, 1287, 495, 963]]}}
{"data": {"events": [[2, 111, 222, 333], [3, 444, 555, 666], [4, 777, 888, 999]]}}
第 2 步 - 处理 theTable 以生成预期的架构(请参阅答案顶部)并保存到最终表格中。您可以为此使用以下查询
SELECT
NTH(1, SPLIT(y)) AS type,
NTH(2, SPLIT(y)) AS metric1,
NTH(3, SPLIT(y)) AS metric2,
NTH(4, SPLIT(y)) AS metric3,
FROM (
SELECT
REPLACE(REPLACE(COALESCE(y0, y1, y2, y3, y4, y5, y6), '[', ''), ']', '') AS y
FROM (
SELECT
IF(k=0, JSON_EXTRACT(data, '$.data.events[0]'), NULL) AS y0,
IF(k=1, JSON_EXTRACT(data, '$.data.events[1]'), NULL) AS y1,
IF(k=2, JSON_EXTRACT(data, '$.data.events[2]'), NULL) AS y2,
IF(k=3, JSON_EXTRACT(data, '$.data.events[3]'), NULL) AS y3,
IF(k=4, JSON_EXTRACT(data, '$.data.events[4]'), NULL) AS y4,
IF(k=5, JSON_EXTRACT(data, '$.data.events[5]'), NULL) AS y5,
IF(k=6, JSON_EXTRACT(data, '$.data.events[6]'), NULL) AS y6,
FROM theTable AS a
CROSS JOIN (
SELECT k FROM (SELECT 0 AS k), (SELECT 1 AS k), (SELECT 2 AS k),
(SELECT 3 AS k), (SELECT 4 AS k), (SELECT 5 AS k), (SELECT 6 AS k)
) AS b
)
HAVING NOT y IS NULL
)
结果将是
type metric1 metric2 metric3
1 1271 518 945
1 1287 495 963
2 111 222 333
3 444 555 666
4 777 888 999
如您所见 - 此特定查询最多支持 7 个子数组,但您可以通过更改三个位置的代码来减少或增加它
#1
REPLACE(REPLACE(COALESCE(y0, y1, y2, y3, y4, y5, y6), '[', ''), ']', '') AS y
#2
IF(k=0, JSON_EXTRACT(data, '$.data.events[0]'), NULL) AS y0,
IF(k=1, JSON_EXTRACT(data, '$.data.events[1]'), NULL) AS y1,
IF(k=2, JSON_EXTRACT(data, '$.data.events[2]'), NULL) AS y2,
IF(k=3, JSON_EXTRACT(data, '$.data.events[3]'), NULL) AS y3,
IF(k=4, JSON_EXTRACT(data, '$.data.events[4]'), NULL) AS y4,
IF(k=5, JSON_EXTRACT(data, '$.data.events[5]'), NULL) AS y5,
IF(k=6, JSON_EXTRACT(data, '$.data.events[6]'), NULL) AS y6,
#3
SELECT k FROM (SELECT 0 AS k), (SELECT 1 AS k), (SELECT 2 AS k),
(SELECT 3 AS k), (SELECT 4 AS k), (SELECT 5 AS k), (SELECT 6 AS k)
最后,只测试转换逻辑,不加载实际数据 - 你可以使用下面的脚本
SELECT
NTH(1, SPLIT(y)) AS type,
NTH(2, SPLIT(y)) AS metric1,
NTH(3, SPLIT(y)) AS metric2,
NTH(4, SPLIT(y)) AS metric3,
FROM (
SELECT
REPLACE(REPLACE(COALESCE(y0, y1, y2, y3, y4, y5, y6), '[', ''), ']', '') AS y
FROM (
SELECT
IF(k=0, JSON_EXTRACT(data, '$.data.events[0]'), NULL) AS y0,
IF(k=1, JSON_EXTRACT(data, '$.data.events[1]'), NULL) AS y1,
IF(k=2, JSON_EXTRACT(data, '$.data.events[2]'), NULL) AS y2,
IF(k=3, JSON_EXTRACT(data, '$.data.events[3]'), NULL) AS y3,
IF(k=4, JSON_EXTRACT(data, '$.data.events[4]'), NULL) AS y4,
IF(k=5, JSON_EXTRACT(data, '$.data.events[5]'), NULL) AS y5,
IF(k=6, JSON_EXTRACT(data, '$.data.events[6]'), NULL) AS y6,
FROM (
SELECT data FROM
(SELECT '{"data": {"events": [[1, 1271, 518, 945], [1, 1287, 495, 963]]}}' AS data),
(SELECT '{"data": {"events": [[2, 111, 222, 333], [3, 444, 555, 666], [4, 777, 888, 999]]}}' AS data)
) AS a
CROSS JOIN (
SELECT k FROM (SELECT 0 AS k), (SELECT 1 AS k), (SELECT 2 AS k),
(SELECT 3 AS k), (SELECT 4 AS k), (SELECT 5 AS k), (SELECT 6 AS k)
) AS b
)
HAVING NOT y IS NULL
)
希望这对您有所帮助!