【问题标题】:Google Apps Script - Adding n Hours to Current Time and DateGoogle Apps 脚本 - 将 n 小时添加到当前时间和日期
【发布时间】:2019-07-05 03:05:02
【问题描述】:

我是 Google Apps 脚本代码的新手,我正在尝试简单地将用户定义的小时数添加到当前时间(例如 12 小时)。然后,该代码将在谷歌文档中插入未来 12 小时的时间和日期。

我使用 ui.prompt 让用户输入他们想要的未来小时数。我拥有的代码没有给我一个错误,但它把当前时间放在未来一些奇怪的天数(不知道它为什么这样做)。这是我拥有的代码,else 部分是我遇到问题的地方...

function UpdateDocument() {

  var document = DocumentApp.getActiveDocument();
  var date = new Date();
  var tomorrow = new Date();
  tomorrow.setDate(tomorrow.getDate()+1);
  var ui = DocumentApp.getUi();

var regExpUpdateDate = "[A-Z]{3}, [A-Z]{3} [A-Z]{1}, [A-Z]{4}"; // Regular expression to find the correct line for the Next Update

  // Ask User if the they want to include the Next Update Line  
  var response = ui.alert('Would you like to include the Next Update line?' , ui.ButtonSet.YES_NO);

  // Process the users response.
  if (response == ui.Button.YES) {
    var responseNextUpdate = ui.prompt('Enter the number of hours you want until the next update (i.e. 12, 24, etc.)' 
                                       + ' or leave blank if you only want to include the date and omit the time. Note that'
                                       + ' leaving it blank will default to the day 24 hours from now.'); // Prompts user for number of hours until the next update
    if (responseNextUpdate.getResponseText() == '') {
      document.replaceText(regExpUpdateDate, Utilities.formatDate(tomorrow, 'America/Denver', 'EEEE, MMMM d, yyyy'));
    }
    else { // This is the section that I am having issues with...
      var userSelectedHours = new Date();
      userSelectedHours.setDate(userSelectedHours.getHours() + 2);
      document.replaceText(regExpUpdateDate, Utilities.formatDate(userSelectedHours, 'America/Denver', 'h a EEEE, MMMM d, yyyy'));
    }
  }
}

【问题讨论】:

    标签: google-apps-script


    【解决方案1】:

    我发现使用毫秒来加/减时间更容易。

      var now = new Date(); // Fri Jul 05 09:53:12 GMT+05:30 2019
    
      var nowInMS = now.getTime(); // 1562300592245
    
      var add = 12 * 60 * 60 * 1000; // 43200000 = 12 hours in milliseconds
    
      var twelveHoursLater = nowInMS + add; // 1562343792245
    
      var futureDate = new Date(twelveHoursLater); // Fri Jul 05 21:53:12 GMT+05:30 2019
    
      var futureDateFormatted = Utilities.formatDate(futureDate, Session.getScriptTimeZone(), "dd-MMM-yy hh:mm a"); // 05-Jul-19 09:53 PM
    

    【讨论】:

      【解决方案2】:

      试试这个:

      function UpdateDocument() {
        var document = DocumentApp.getActiveDocument();
        var date = new Date();
        var tomorrow = new Date();
        tomorrow.setDate(tomorrow.getDate()+1);
        var ui = DocumentApp.getUi();
        var regExpUpdateDate = "[A-Z]{3}, [A-Z]{3} [A-Z]{1}, [A-Z]{4}"; 
        var response = ui.alert('Would you like to include the Next Update line?' , ui.ButtonSet.YES_NO);
        if (response == ui.Button.YES) {
          var responseNextUpdate = ui.prompt('Enter the number of hours you want until the next update (i.e. 12, 24, etc.) or leave blank if you only want to include the date and omit the time. Note that leaving it blank will default to the day 24 hours from now.');
          if (responseNextUpdate.getResponseText() == '') {
            document.replaceText(regExpUpdateDate, Utilities.formatDate(tomorrow, 'America/Denver', 'EEEE, MMMM d, yyyy'));
          }
          else { // This is the section that I am having issues with...
            var hours=Number(responseNextUpdate.getResponseText());
            var delayedDate =new Date(new Date().setHours(new Date().getHours() + hours));
            document.replaceText(regExpUpdateDate, Utilities.formatDate(delayedDate, 'America/Denver', 'h a EEEE, MMMM d, yyyy'));
            Logger.log(Utilities.formatDate(delayedDate, 'America/Denver', 'h a EEEE, MMMM d, yyyy'));
          }
        }
      }
      

      【讨论】:

        【解决方案3】:

        我遇到了同样的问题,从变量中获取数据并合并到一个新变量中。下面我复制部分代码。它并不顺利,但它正在工作......

          // The commands in the next lines were required to combine date and time
          // event_values[7] corresponds to the date of the event provided by the form to the spreadsheet as dd/MM/yyyy
          var day = new Date(event_values[7].toLocaleString()).getDate().valueOf();
          var month=new Date(event_values[7].toLocaleString()).getMonth().valueOf();
          var year=new Date(event_values[7].toLocaleString()).getFullYear().valueOf();
          // event_values[8] and [9] correspond to the start and end time of the event as HH:mm:ss also provided by the form to the spreadsheet
          var start_time=event_values[8].toString().split(":");
          // since the day was not provided for the start_time and end_time variables, in my case the script assumed as 1899. So I split the string first with ":" and then with "1899 ".
          var start_hour=start_time[0].split("1899 ")[1].valueOf();
          var start_min=start_time[1].valueOf();
          var end_time=event_values[9].toString().split(":")
          var end_hour=end_time[0].split("1899 ")[1].valueOf();
          var end_min=end_time[1].valueOf();
        
          var event_start_time = new Date(year,month,day,start_hour,start_min,"00");
          var event_end_time=new Date(year,month,day,end_hour,end_min,"00");
        

        【讨论】:

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