BigQuery 逗号分隔的字符串评估

Question

我正在使用 BigQuery，我正在尝试解析逗号分隔的字符串以查找其中的特定数字。

示例表如下

|--------|-----------------------------------------------------------|
| userID | sequence                                                  |
|--------|-----------------------------------------------------------|
| 123abc | 1,2,3,4,5,6,7,8                                           |                                          
|--------|-----------------------------------------------------------|
| 456bcd | 1,2,3,4,5,6,7,8,9,10,11                                   |
|--------|-----------------------------------------------------------|
| 789def | 1,2,3,4                                                   |
|--------|-----------------------------------------------------------|

我需要创建一个 CASE 语句，其中字符串“序列”的每个值都根据以下逻辑进行评估，并将结果输出到它自己的列。

SELECT userID
,sequence
,CASE WHEN sequence CONTAINS '1' THEN 1 ELSE 0 END AS action1 
,CASE WHEN sequence CONTAINS '2' THEN 1 ELSE 0 END AS action2 
,CASE WHEN sequence CONTAINS '3' THEN 1 ELSE 0 END as action3
....
,CASE WHEN sequence CONTAINS '9' AND '11' THEN 1 ELSE 0 END as action10

这将产生以下输出。

|--------|-------------------------|-------|-------|-------|---------|
| userID | sequence                |action1|action2|action3|action10 |
|--------|-------------------------|-------|-------|-------|---------|
| 123abc | 1,2,3,4,5,6,7,8         |   1   |   1   |   1   |    0    |                                          
|--------|-------------------------|-------|-------|-------|---------|
| 456bcd | 1,2,3,4,5,6,7,8,9,10,11 |   1   |   1   |   1   |    1    |
|--------|-------------------------|-------|-------|-------|---------|
| 789def | 1,2                     |   1   |   1   |   0   |    0    |
|--------|-------------------------|-------|-------|-------|---------|

请不要最后一个 CASE WHEN 语句非常重要，因为我需要将这种非常具体的字符串值组合作为其自己的独特操作。

我相信这可以在 SQL Server 中使用类似的方式实现：

CASE WHEN CHARINDEX('1', 'sequence')>0 THEN 1 ELSE 0 END as action1
,CASE WHEN CHARINDEX('2', 'sequence')>0 THEN 1 ELSE 0 END as action2
,CASE WHEN CHARINDEX('3', 'sequence')>0 THEN 1 ELSE 0 END as action3
...
,CASE WHEN CHARINDEX('9', 'sequence')>0 AND CHARINDEX('11', 'sequence')>0 THEN 1 ELSE 0 END as action10

但是，我在 BigQuery 中找不到可以达到相同结果的等效函数，而且我在 REGEX 上的尝试也失败了。

我将非常感谢您在这里提供一些指导。提前致谢。

Answer 1

请参阅下面的说明（适用于 BigQuery 标准 SQL）

#standardSQL
WITH `project.dataset.table` AS (
  SELECT '123abc' userID, '1,2,3,4,5,6,7,8' sequence UNION ALL
  SELECT '456bcd', '1,2,3,4,5,6,7,8,9,10,11' UNION ALL
  SELECT '789def', '1,2' 
)
SELECT userID, 
  IF((SELECT COUNT(1) FROM UNNEST(SPLIT(sequence)) value WHERE value = '1' ) > 0, 1, 0)  action1,
  IF((SELECT COUNT(1) FROM UNNEST(SPLIT(sequence)) value WHERE value = '2' ) > 0, 1, 0)  action2,
  IF((SELECT COUNT(1) FROM UNNEST(SPLIT(sequence)) value WHERE value = '3' ) > 0, 1, 0)  action3,
  IF((SELECT COUNT(1) FROM UNNEST(SPLIT(sequence)) value WHERE value = '4' ) > 0, 1, 0)  action4,
  IF((SELECT COUNT(1) FROM UNNEST(SPLIT(sequence)) value WHERE value = '5' ) > 0, 1, 0)  action5,
  IF((SELECT COUNT(1) FROM UNNEST(SPLIT(sequence)) value WHERE value = '6' ) > 0, 1, 0)  action6,
  IF((SELECT COUNT(1) FROM UNNEST(SPLIT(sequence)) value WHERE value = '7' ) > 0, 1, 0)  action7,
  IF((SELECT COUNT(1) FROM UNNEST(SPLIT(sequence)) value WHERE value = '8' ) > 0, 1, 0)  action8,
  IF((SELECT COUNT(1) FROM UNNEST(SPLIT(sequence)) value WHERE value = '9' ) > 0, 1, 0)  action9,
  IF((SELECT COUNT(1) FROM UNNEST(SPLIT(sequence)) value WHERE value IN ('10', '11' )) > 0, 1, 0)  action10
FROM `project.dataset.table`
-- ORDER BY userID  

这将为您提供如下所示的内容

Row userID  action1 action2 action3 action4 action5 action6 action7 action8 action9 action10     
1   123abc  1       1       1       1       1       1       1       1       0       0    
2   456bcd  1       1       1       1       1       1       1       1       1       1    
3   789def  1       1       0       0       0       0       0       0       0       0      

它被简化了——但是按照你的要求给你some guidance :o)

请参阅下面的重构想法（通常是无休止的过程），因此至少不那么冗长

#standardSQL
WITH `project.dataset.table` AS (
  SELECT '123abc' userID, '1,2,3,4,5,6,7,8' sequence UNION ALL
  SELECT '456bcd', '1,2,3,4,5,6,7,8,9,10,11' UNION ALL
  SELECT '789def', '1,2' 
)
SELECT userID, 
  IF('1' IN UNNEST(SPLIT(sequence)), 1, 0) AS action1,
  IF('2' IN UNNEST(SPLIT(sequence)), 1, 0) AS action2,
  IF('3' IN UNNEST(SPLIT(sequence)), 1, 0) AS action3,
  IF('4' IN UNNEST(SPLIT(sequence)), 1, 0) AS action4,
  IF('5' IN UNNEST(SPLIT(sequence)), 1, 0) AS action5,
  IF('6' IN UNNEST(SPLIT(sequence)), 1, 0) AS action6,
  IF('7' IN UNNEST(SPLIT(sequence)), 1, 0) AS action7,
  IF('8' IN UNNEST(SPLIT(sequence)), 1, 0) AS action8,
  IF('9' IN UNNEST(SPLIT(sequence)), 1, 0) AS action9,
  IF((SELECT COUNT(1) FROM UNNEST(SPLIT(sequence)) value WHERE value IN ('10', '11' )) > 0, 1, 0)  action10
FROM `project.dataset.table`

更新以解决有关 UNION ALL 的 cmets

上面使用了您问题中的虚拟数据，以便您可以测试、使用它 - 同时解决方案实际上是

#standardSQL
SELECT userID, 
  IF('1' IN UNNEST(SPLIT(sequence)), 1, 0) AS action1,
  IF('2' IN UNNEST(SPLIT(sequence)), 1, 0) AS action2,
  IF('3' IN UNNEST(SPLIT(sequence)), 1, 0) AS action3,
  IF('4' IN UNNEST(SPLIT(sequence)), 1, 0) AS action4,
  IF('5' IN UNNEST(SPLIT(sequence)), 1, 0) AS action5,
  IF('6' IN UNNEST(SPLIT(sequence)), 1, 0) AS action6,
  IF('7' IN UNNEST(SPLIT(sequence)), 1, 0) AS action7,
  IF('8' IN UNNEST(SPLIT(sequence)), 1, 0) AS action8,
  IF('9' IN UNNEST(SPLIT(sequence)), 1, 0) AS action9,
  IF((SELECT COUNT(1) FROM UNNEST(SPLIT(sequence)) value WHERE value IN ('10', '11' )) > 0, 1, 0)  action10
FROM `project.dataset.table`