过去 4 天每 15 分钟按列计数

Question

我有这个查询，它每 15 分钟输出一次有多少“否”收到。

select trunc(rcv_dt,'hh24') + (trunc(to_char(rcv_dt,'mi')/15)*15)/24/60 as timeline, count(distinct(NO)) as count
from tbl where trunc(rcv_dt) = trunc(SYSDATE -1)
group by  trunc(rcv_dt,'hh24') + (trunc(to_char(rcv_dt,'mi')/15)*15)/24/60
order by trunc(rcv_dt,'hh24') + (trunc(to_char(rcv_dt,'mi')/15)*15)/24/60

输出：

但是，我需要最近几天的类似数据，格式如下。在这方面需要你的帮助。

Answer 1

我认为这是你想要的：

select (trunc(to_char(rcv_dt, 'mi')/15)*15)/24/60 as timeline, 
       count(distinct case when trunc(rcv_dt,'hh24') = date '2019-03-13' then NO end) as no_20190313,
       count(distinct case when trunc(rcv_dt,'hh24') = date '2019-03-12' then NO end) as no_20190312,
       count(distinct case when trunc(rcv_dt,'hh24') = date '2019-03-11' then NO end) as no_20190311
from tbl
where trunc(rcv_dt) >= date '2019-03-11'
group by (trunc(to_char(rcv_dt,'mi')/15)*15)/24/60
order by (trunc(to_char(rcv_dt,'mi')/15)*15)/24/60;