【发布时间】:2014-01-14 16:44:54
【问题描述】:
我希望能够计算一个矩形相对于矩形网格的 Jaccard 分数/距离(距离为 1 分)。我的网格是 50x50(总共 1625625 个矩形)。
我能够在 0.34 秒内针对所有这些计算输入矩形的分数,但这还不够快,因为我要么需要能够处理 10k 矩形,要么将结果存储在数据库中(更新 10 秒每次调用数千行)。所以我希望让数据库为我做计算,而不必从数据库中提取任何东西,但是我想不出没有游标如何做到这一点......
sourceRectangles 包含我的单个矩形(虽然实际上会有 10k),rectangles 包含我的网格,temporaryRectangleList 包含分数的总和。
Dictionary<UInt32, Rectangle> temporaryRectangleList = new Dictionary<UInt32, Rectangle>();
foreach (var sourceRectangle in sourceRectangles)
{
foreach (var rectangle in rectangles)
{
// For each rectangle within the group
//foreach (var rectangle in group)
//{
int max_MinX = Math.Max(sourceRectangle.MinX, rectangle.MinX);
int min_MaxX = Math.Min(sourceRectangle.MaxX, rectangle.MaxX);
// There is an overlap
//if (max_MinX < min_MaxX)
//{
int max_MinY = Math.Max(sourceRectangle.MinY, rectangle.MinY);
int min_MaxY = Math.Min(sourceRectangle.MaxY, rectangle.MaxY);
// Calculate the area of the overlap
int area = ((min_MaxX - max_MinX)*(min_MaxY - max_MinY));
// Store the Jaccard score
var score = (double) area/((sourceRectangle.Area + rectangle.Area) - area);
if (temporaryRectangleList.ContainsKey(rectangle.ID))
{
temporaryRectangleList[rectangle.ID].Weight += score;
}
else
{
temporaryRectangleList.Add(rectangle.ID, new Rectangle(rectangle, score));
}
}
}
我需要能够在字典中查找项目,因为我需要通过矩形的 ID 从中提取数据。
如果你认为你可以加快 C# 速度以更快(10k 矩形处理
很遗憾,SQL表太大,这里不能转储,所以我只能给你结构:
USE [Rectangles]
GO
/****** Object: Table [dbo].[PreProcessed] Script Date: 14/01/2014 16:39:33 ******/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
CREATE TABLE [dbo].[PreProcessed](
[ID] [int] NOT NULL,
[MinX] [int] NOT NULL,
[MinY] [int] NOT NULL,
[MaxX] [int] NOT NULL,
[MaxY] [int] NOT NULL,
[Area] [int] NOT NULL,
CONSTRAINT [PK_PreProcessed] PRIMARY KEY CLUSTERED
(
[ID] ASC,
[Area] ASC
)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY]
GO
矩形类:
public class Rectangle
{
public Rectangle(UInt32 id, int minX, int maxX, int minY, int maxY, double weight)
{
ID = id;
MinX = minX;
MaxX = maxX;
MinY = minY;
MaxY = maxY;
Area = (maxX - minX)*(maxY - minY);
Weight = weight;
}
public Rectangle(Rectangle input, double weight)
{
ID = input.ID;
MinX = input.MinX;
MaxX = input.MaxX;
MinY = input.MinY;
MaxY = input.MaxY;
Area = input.Area;
Weight = weight;
}
public int Area { get; set; }
public int MinX { get; set; }
public int MaxX { get; set; }
public int MinY { get; set; }
public int MaxY { get; set; }
public UInt32 ID { get; set; }
public double Weight { get; set; }
}
【问题讨论】:
-
如果你可以切换内部和外部循环,你可以摆脱字典查找,你可以内联 Math.Max 和 Math.Min。在我的小测试中,我通过将 Retangle 从类更改为结构(并使成员字段而不是属性)获得了最大的好处。
标签: c# sql performance distance overlap