按下时更改 UIButton 颜色

Question

我试图让一个按钮在被选中时突出显示为紫色，并将所有其他按钮返回到它们的取消选中状态。

我为每个按钮创建了 IBOutlets：

@property (strong, nonatomic) IBOutlet UIButton *oneButton;
@property (strong, nonatomic) IBOutlet UIButton *twoButton;
@property (strong, nonatomic) IBOutlet UIButton *threeButton;
@property (strong, nonatomic) IBOutlet UIButton *fourButton;
@property (strong, nonatomic) IBOutlet UIButton *fiveButton;

合成它们：

@synthesize oneButton, twoButton, threeButton, fourButton, fiveButton;

并且我正在尝试制定一种方法来遍历所有这些，突出显示正确的方法并取消突出显示其余部分。我能去工作的唯一方法是乏味的方式。我知道必须有更简单的方法。

这也将停用按钮的背景颜色设置为 lightGrayColor，但我希望它们返回到它们的起始颜色，即界面中的 Mercury 蜡笔颜色。

- (IBAction)btnClick:(id)sender {

if (self.oneButton == sender) {
    [self.oneButton setBackgroundColor:[UIColor purpleColor]];
    [self.twoButton setBackgroundColor:[UIColor lightGrayColor]];
    [self.threeButton setBackgroundColor:[UIColor lightGrayColor]];
    [self.fourButton setBackgroundColor:[UIColor lightGrayColor]];
    [self.fiveButton setBackgroundColor:[UIColor lightGrayColor]];

} else if (self.twoButton == sender) {
    [self.oneButton setBackgroundColor:[UIColor lightGrayColor]];
    [self.twoButton setBackgroundColor:[UIColor purpleColor]];
    [self.threeButton setBackgroundColor:[UIColor lightGrayColor]];
    [self.fourButton setBackgroundColor:[UIColor lightGrayColor]];
    [self.fiveButton setBackgroundColor:[UIColor lightGrayColor]];

} else if (self.threeButton == sender) {
    [self.oneButton setBackgroundColor:[UIColor lightGrayColor]];
    [self.twoButton setBackgroundColor:[UIColor lightGrayColor]];
    [self.threeButton setBackgroundColor:[UIColor purpleColor]];
    [self.fourButton setBackgroundColor:[UIColor lightGrayColor]];
    [self.fiveButton setBackgroundColor:[UIColor lightGrayColor]];

} else if (self.fourButton == sender) {
    [self.oneButton setBackgroundColor:[UIColor lightGrayColor]];
    [self.twoButton setBackgroundColor:[UIColor lightGrayColor]];
    [self.threeButton setBackgroundColor:[UIColor lightGrayColor]];
    [self.fourButton setBackgroundColor:[UIColor purpleColor]];
    [self.fiveButton setBackgroundColor:[UIColor lightGrayColor]];

} else if (self.fiveButton == sender) {
    [self.oneButton setBackgroundColor:[UIColor lightGrayColor]];
    [self.twoButton setBackgroundColor:[UIColor lightGrayColor]];
    [self.threeButton setBackgroundColor:[UIColor lightGrayColor]];
    [self.fourButton setBackgroundColor:[UIColor lightGrayColor]];
    [self.fiveButton setBackgroundColor:[UIColor purpleColor]];
}

Answer 1

首先，只要不同时定义 getter 和 setter，就不再需要综合属性。

其次，这应该更容易。

NSArray *buttons = @[self.oneButton, ..., self.fiveButton];
[buttons makeObjectsPerformSelector:@selector(setBackgroundColor:) withObject:UIColor.lightGrayColor];
sender.backgroundColor = UIColor.purpleColor;