对成员 Swift 3 的模糊引用

Question

我正在将我的项目从 Swift 2.3 迁移到 Swift 3。并且遇到了预期的困难。

这是一个用于 OAuth 的函数，使用 OAuthSwift。我试图转换

class func OAuthSwiftAuthorization(inViewController viewController: UIViewController, withOAuthInfo info:FitnessTracker, successHandler:@escaping MyOAuthNewSuccessHandler, failure: @escaping ((_ error: NSError) -> Void)) {

    let oauthswift = OAuth2Swift(
        consumerKey:    info.consumerKey,
        consumerSecret: info.consumerSecret,
        authorizeUrl:   info.authorizeUrl,
        accessTokenUrl: info.accessTokenUrl,
        responseType:   info.responseType
    )

    oauthswift.authorizeURLHandler = SafariURLHandler(viewController: viewController, oauthSwift: oauthswift)
    oauthswift.accessTokenBasicAuthentification = true
    oauthswift.allowMissingStateCheck = true

    oauthswift.authorize(withCallbackURL: URL(string: info.callBackUrl)!, scope: info.scope, state: info.state, success: { (credential, response, parameters) in

             successHandler(credential, response, parameters)
    }) { (error) in

        failure(error: error)
        print(error.localizedDescription)
    }
}

但我在

处遇到错误

oauthswift.authorize(withCallbackURL: URL(string: info.callBackUrl)!, scope: info.scope, state: info.state, success: { (credential, response, parameters) in

错误状态

对成员'authorize(withCallbackURL:scope:state:parameters:headers:success:failure:)'的模糊引用

这是 Swift 2 的工作代码。

    oauthswift.authorizeWithCallbackURL(
        URL(string: info.callBackUrl)!,
        scope: info.scope, state:info.state,
        success: { credential, response, parameters in

            successHandler(credientials: credential, response: response, params: parameters)
        },
        failure: { error in

            failure(error: error)
            print(error.localizedDescription)
        }
    )

更新：

在我键入成功和失败处理程序之前不会出现错误。这很好：

        oauthswift.authorize(withCallbackURL: URL(string: info.callBackUrl)!, scope: info.scope, state: info.state, success: { (credential, response, parameters) in
        // successHandler(credential, response, parameters)
    }) { (erorr) in
        // failure(error: error
    }

所以请指导我谢谢。

Answer 1

我认为这个问题是由于 Swift 的类型推断结合闭包的一些缺点造成的。 您可以尝试以下方法之一：

不要使用尾随闭包，例如

oauthswift.authorize(withCallbackURL: URL(string: info.callBackUrl)!, scope: info.scope, state: info.state, success: { (credential, response, parameters) in

         successHandler(credential, response, parameters)
}, failure: { (error) in

    failure(error: error)
    print(error.localizedDescription)
})

或为错误提供明确的类型，例如

 oauthswift.authorize(withCallbackURL: URL(string: info.callBackUrl)!, scope: info.scope, state: info.state, success: { (credential, response, parameters) in

         successHandler(credential, response, parameters)
 }) { (error: Error) in

     failure(error: error)
     print(error.localizedDescription)
 }

Answer 2

供参考： 当存在多个同名变量/方法时会出现这种错误，您的oauthswift 是否有多个称为“授权”的“事物”？像另一种方法？ 我的错误是我声明：

let fileManager = FileManager()

在

let _ = try localFileManager.createDirectory(...) 

我遇到了同样的错误，更改 localFileManager 中的变量名修复了它。

Answer 3

我在将其从 Swift 4 转换为 Swift 5 时遇到了相同的错误 Ambiguous reference to member。看起来完成处理程序已更改为支持新的 Result 类型。将完成处理程序更改为以下解决了我的问题，

        oauthVarSwift.authorize( withCallbackURL: URL(string: "")!,
                             scope: "", state:"", completionHandler: {  result in
                                switch result {
                                case .success(let credential, let response,  let parameters):
                                    print(credential.oauthToken)

                                case .failure(let error):
                                 print(error)
                                }

          })