使用 swift 2.0 生成钥匙串密钥

Question

创建密钥对（私有、公共）的函数

public func generateKeyPair(publicKeyTag: String, privateKeyTag:String, keySize: Int) -> KeyPair? {

    let privateKeyAttr: [String: AnyObject] = [
        kSecAttrIsPermanent as String: kCFBooleanTrue,
        kSecAttrApplicationTag as String: privateKeyTag
    ];

    let publicKeyAttr: [String: AnyObject] = [
        kSecAttrIsPermanent as String: kCFBooleanTrue,
        kSecAttrApplicationTag as String: publicKeyTag
    ];

    let keyPairAttr: [String: AnyObject] = [
        kSecAttrKeyType as! String: kSecAttrKeyTypeRSA,
        kSecAttrKeySizeInBits as! String: keySize,
        kSecPrivateKeyAttrs as! String: privateKeyAttr,
        kSecPublicKeyAttrs as! String: publicKeyAttr
    ];

    var publicKeyPtr, privateKeyPtr: Unmanaged<SecKey>?;

    let error = SecKeyGeneratePair(keyPairAttr, &publicKeyPtr, &privateKeyPtr)

    if( result != errSecSuccess ){
        return nil
    }

    let publicKey = publicKeyPtr!.takeRetainedValue()
    let privateKey = privateKeyPtr!.takeRetainedValue()
    return KeyPair(publicKey: publicKey, privateKey: privateKey)
}

加注

Cannot convert value of type 'inout Unmanged<SecKey>?' ... expected argument type 'UnsafeMutablePointer<SecKey?> ...'

当我查找 the api for SecKeyGeneratePair 时，这听起来是 sound，所以让我们更改 publicKeyPtr, privateKeyPtr 的类型：

public func generateKeyPair(publicKeyTag: String, privateKeyTag:String, keySize: Int) -> KeyPair ? {

    let privateKeyAttr: [String: AnyObject] = [
        kSecAttrIsPermanent as String: kCFBooleanTrue,
        kSecAttrApplicationTag as String: privateKeyTag
    ]

    let publicKeyAttr: [String: AnyObject] = [
        kSecAttrIsPermanent as String: kCFBooleanTrue,
        kSecAttrApplicationTag as String: publicKeyTag
    ]

    let parameters: [String: AnyObject] = [
        kSecAttrKeyType as String: kSecAttrKeyTypeRSA,
        kSecAttrKeySizeInBits as String: keySize,
        kSecPrivateKeyAttrs as String: privateKeyAttr,
        kSecPublicKeyAttrs as String: publicKeyAttr
    ]

    var publicKeyPtr: UnsafeMutablePointer<SecKey?> = nil
    var privateKeyPtr: UnsafeMutablePointer<SecKey?> = nil

    let result = SecKeyGeneratePair(parameters, publicKeyPtr, privateKeyPtr)

    if( result != errSecSuccess ){
        return nil
    }

    let publicKey = Unmanaged<SecKey>.fromOpaque(COpaquePointer(publicKeyPtr)).takeRetainedValue()
    let privateKey = Unmanaged<SecKey>.fromOpaque(COpaquePointer(privateKeyPtr)).takeRetainedValue()

    publicKeyPtr.destroy()
    privateKeyPtr.destroy()

    return KeyPair(publicKey: publicKey, privateKey: privateKey)
}

但是当我使用该函数时，publicKey 和 privateKey 会引发：

Thread 1: EXC_BAD_INSTRUCTION (code=EXC_i386_INVOP, ...

当我插入断点时，我意识到指针（`publicKeyPtr，privateKeyPtr）从未设置。

那么如何将 swift 1.2 代码迁移到 swift 2.0 呢？

Answer 1

试试：

public func generateKeyPair(publicKeyTag: String, privateKeyTag:String, keySize: Int) -> KeyPair?  {

    let privateKeyAttr: [NSString: AnyObject] = [
        kSecAttrIsPermanent: true,
        kSecAttrApplicationTag: privateKeyTag
    ]
    let publicKeyAttr: [NSString: AnyObject] = [
        kSecAttrIsPermanent: true,
        kSecAttrApplicationTag: publicKeyTag
    ]
    let parameters: [NSString: AnyObject] = [
        kSecAttrKeyType: kSecAttrKeyTypeRSA,
        kSecAttrKeySizeInBits: keySize,
        kSecPrivateKeyAttrs: privateKeyAttr,
        kSecPublicKeyAttrs: publicKeyAttr
    ]

    var publicKey: SecKey?
    var privateKey: SecKey?
    let result = SecKeyGeneratePair(parameters, &publicKey, &privateKey)

    if result != errSecSuccess {
        return nil
    }
    return KeyPair(publicKey: publicKey!, privateKey: privateKey!)
}

您可以将& 表达式传入-传出UnsafeMutablePointer 参数。

另请参阅：swift 2.0 keychain type errors for SecItemCopyMatching