快速访问不同节点的firebase数据库

Question

我仍在尝试访问所有节点，但是当我编写此代码时，我收到了下面写的错误。如果这项运动在我的数据库中，我想为高尔夫打印“是”。

在let dict = snap.value as! [String: any] 行之前一切正常。即我可以写不同的快照，但它会崩溃。

我的数据库中的所有元素都是字符串，甚至是坐标。您可以通过下面的链接找到我的数据库图片。

@IBAction func testbutton(_ sender: UIButton) {
    Database.database().reference().child("users").observe(.childAdded) { (snapshot) in
       for child in snapshot.children {
        print(child)
            let snap = child as! DataSnapshot
            print(snap)
            let dict = snap.value as! [String: Any]
            let msg = dict["golf"] as! String
            print(msg)

错误：

___________________________________________________
Could not cast value of type 'NSTaggedPointerString' 
(0x7fff87a91958) to 'NSDictionary' (0x7fff87a91c78).
2020-07-21 13:18:24.131870+0200 Joiny[43447:2152693] 
Could not cast value of type 'NSTaggedPointerString' 
(0x7fff87a91958) to 'NSDictionary' (0x7fff87a91c78).
_______________________________________________________

我的数据库图片 ->

Answer 1

你需要

Database.database().reference().child("users").observe(.childAdded) { (snapshot) in  
  let dict = snapshot.value as! [String: Any]
  let res = dict["golf"] as! [String: Any]
  let msg = res["golf"] as! String
  print(msg)
}