如何创建弹出视图？

Question

如何在 xcode 4 中以编程方式创建弹出视图？ 我正在尝试创建一个弹出视图，其中包含一个 webview 我在视图中添加了一个后退按钮。我想转到按下后退按钮时调用它的上一个视图。 我该怎么做？？

Answer 1

使用它并根据需要自定义它们

https://github.com/sonsongithub/PopupView

Answer 2

步骤：1 - 在 storyboard 中创建新的 VC，在 VC 中创建新的 UIView。将其命名为 (ViewPopupUI)，然后在 ViewPopupUI 中声明所需的字段和属性。

步骤：2 - VC 内部

@IBOutlet private weak var viewPopupUI:UIView!
@IBOutlet var btnClose: UIButton!

override func viewDidLoad() {
    super.viewDidLoad()

   self.showViewWithAnimation()
}

@IBAction func btnCloseAction(_ sender: Any) {

    self.hideViewWithAnimation()
}

 //MARK: - Animation Method
private func showViewWithAnimation() {

    self.view.alpha = 0
    self.viewPopupUI.transform = CGAffineTransform(scaleX: 0.1, y: 0.1)

    UIView.animate(withDuration: 0.3) {
        self.viewPopupUI.transform = CGAffineTransform(scaleX: 1.0, y: 1.0)
        self.view.alpha = 1
    }
}

private func hideViewWithAnimation() {

    UIView.animate(withDuration: 0.3, animations: {

        self.viewPopupUI.transform = CGAffineTransform(scaleX: 0.1, y: 0.1)
        self.view.alpha = 0

    }, completion: {
        (value: Bool) in

        self.removeFromParent()
        self.view.removeFromSuperview()
    })
}

来电弹窗

let popupVC = storyboard?.instantiateViewController(withIdentifier: "SchoolEventGoingPopup_VC") as! SchoolEventGoingPopup_VC
    popupVC.strId =  self.dictEventDetails?.object(forKey: "id") as? Int
    view.addSubview(popupVC.view)
    addChildViewController(popupVC)