NSArray 中的 iOS sdk NSArray 查找和合并答案

【问题标题】：iOS sdk NSArray within NSArray find and mergeNSArray 中的 iOS sdk NSArray 查找和合并
【发布时间】：2017-02-21 04:43:40
【问题描述】：

我正在尝试在多个 NSArray 中搜索和合并对象。

基本上 NSArray 具有多个 NSArray 和 1 个对象，然后是 NSDictionary。我想检查对象是否已经存在并将其与现有对象合并，那么它将是 NSSArray，它有一个 NSArray 和 1 个对象，然后是多个 NSDictionary。在 Objective-c 中。

(
  (
    "The Essential: Céline Dion",
    {
      "album": "The Essential: Céline Dion",
      "artwork": "<UIImage: 0x608000087210>, {512, 506}",
      "title": "It's All Coming Back to Me Now"
    }
  ),
  (
    "Ah Via Musicom",
    {
      "album": "Ah Via Musicom",
      "artwork": "<UIImage: 0x60000008a6e0>, {600, 600}",
      "title": "Cliffs of Dover"
    }
  ),
  (
    "Tears Roll Down (Greatest Hits 82-92)",
    {
      "album": "Tears Roll Down (Greatest Hits 82-92)",
      "artwork": "<UIImage: 0x6080000887a0>, {512, 512}",
      "title": "Everybody Wants to Rule the World"
    }
  ),
  (
    "No Money - Single",
    {
      "album": "No Money - Single",
      "artwork": "<UIImage: 0x6080000845b0>, {600, 600}",
      "title": "No Money"
    }
  ),
  (
    "Tears Roll Down (Greatest Hits 82-92)",
    {
      "album": "Tears Roll Down (Greatest Hits 82-92)",
      "artwork": "<UIImage: 0x60800008d5c0>, {512, 512}",
      "title": "Shout"
    }
  ),
  (
    "STAB!",
    {
      "album": "STAB!",
      "artwork": "<UIImage: 0x60800008da20>, {512, 512}",
      "title": "Will You Remember Me?"
    }
  ),
  (
    "Life After Sundown",
    {
      "album": "Life After Sundown",
      "artwork": "<UIImage: 0x60000008d840>, {600, 600}",
      "title": "Werewolves On Wheels"
    }
  )
)

到这里

(
  (
    "The Essential: Céline Dion",
    {
      "album": "The Essential: Céline Dion",
      "artwork": "<UIImage: 0x608000087210>, {512, 506}",
      "title": "It's All Coming Back to Me Now"
    }
  ),
  (
    "Ah Via Musicom",
    {
      "album": "Ah Via Musicom",
      "artwork": "<UIImage: 0x60000008a6e0>, {600, 600}",
      "title": "Cliffs of Dover"
    }
  ),
  (
    "Tears Roll Down (Greatest Hits 82-92)",
    {
      "album": "Tears Roll Down (Greatest Hits 82-92)",
      "artwork": "<UIImage: 0x6080000887a0>, {512, 512}",
      "title": "Everybody Wants to Rule the World"
    },
    {
      "album": "Tears Roll Down (Greatest Hits 82-92)",
      "artwork": "<UIImage: 0x60800008d5c0>, {512, 512}",
      "title": "Shout"
    }
  ),
  (
    "No Money - Single",
    {
      "album": "No Money - Single",
      "artwork": "<UIImage: 0x6080000845b0>, {600, 600}",
      "title": "No Money"
    }
  ),
  (
    "STAB!",
    {
      "album": "STAB!",
      "artwork": "<UIImage: 0x60800008da20>, {512, 512}",
      "title": "Will You Remember Me?"
    }
  ),
  (
    "Life After Sundown",
    {
      "album": "Life After Sundown",
      "artwork": "<UIImage: 0x60000008d840>, {600, 600}",
      "title": "Werewolves On Wheels"
    }
  )
)

【问题讨论】：

样本不一样。第二个显示 Tears Roll Down (Greatest Hits 82-92) 以我想要的方式合并在一起。

标签： ios objective-c iphone nsarray nsdictionary

【解决方案1】：

我们将您的原始数组称为mainArray。

首先，您从 mainArray 收集唯一名称。

NSMutableArray *uniqueNames = [NSMutableArray array];

for (NSArray *sub in mainArray) {
    NSString *name = [sub firstObject];
    BOOL isDuplicate = [[uniqueNames filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"SELF contains %@",name]] count] > 0;
    if (!isDuplicate) {
        [uniqueNames addObject:name];
    }
}

之后，循环遍历 uniqueNames 数组并在 mainArray 中搜索重复项并重新构建数组。

NSMutableArray *final = [NSMutableArray array];
for (NSString *name in uniqueNames) {
    NSPredicate *namePredicate = [NSPredicate predicateWithFormat:@"SELF contains %@",name];
    NSArray *duplicateArrays = [mainArray filteredArrayUsingPredicate:namePredicate];
    if ([duplicateArrays count] > 1) {
        NSMutableArray *newArray = [NSMutableArray arrayWithObject:name];
        for (NSArray *duplicateArray in duplicateArrays) {
            [newArray addObject:[duplicateArray lastObject]];
        }
        [final addObject:newArray];
    }
    else{
        [final addObject:duplicateArrays];
    }
}

final 数组就是你的结果。

【讨论】：