在 Swift 中为 Firebase 数据结构创建类

Question

我是 firebase 新手，创建了一个 Firebase 结构供我使用，我要做的基本上是列出 FirebaseDB 的所有用户。

我想在下面的firebase数据结构中快速创建一个对应的类。

 "users" : {
    "A654tdC5uBPoKQzJnpZIpwOfsaJ3" : {
      "groups" : {
        "-KZ7fl3I4W7YWuGk6l9k" : true,
        "-KclzmvvJF54cAg14P92" : true,
        "-KclzpzrJOhCOWL5_jvw" : true,
        "-Kcm33N1B_oiVYrQWh3n" : true,
        "-Kcm3GfRaaGfztEBmflp" : true
      },
      "location" : {
        "coordinates" : [ 6.59086, 3.3914267 ],
        "name" : "Oyebanjo Solarin Street, Lagos",
        "visibility" : true
      },
      "photoUrl" : "http://pbs.twimg.com/profile_images/511567946351923201/YBqqKc78_normal.jpeg",
      "username" : "Kamiye",
      "visibilityToSelectContacts" : {
        "contacts" : {
          "gFTCpzgSJDOsrVKWbAJp0Z1JFXp1" : true,
          "rRxT6x87kgSjTwZfa7M8ZwzdFkC3" : true
        },
        "visibility" : true
      }
    },

这是我尝试过的，但它不起作用

class LContact {

var visibliityToSelectedContacts: VisibilityToSelectContacts?
var photoUrl: String?
let username: String
var location: LALocation?
var groudId = [String]()


init (value: [String: Any] ) {
    self.username = value["username"] as! String
    self.photoUrl = value["photoUrl"] as? String
    self.location = LALocation(value: value["coordinates"] as? [String:Any] ?? [:])
    self.groudId = (value["groups"] as? [String])!
  }
}

class VisibilityToSelectContacts {

var contacts = [String]()
var visibility: Bool

init(value: [String: Any]) {
    self.contacts = [value["contacts"] as! String]
    self.visibility = value["visibility"] as! Bool
  }
}

struct LALocation {

var long: Double
var lat: Double
var address: String!
var visibility: Bool!

init(long: Double, lat: Double, address: String?, visibility: Bool) {
    self.long = long
    self.lat = lat
    self.address = address
    self.visibility = visibility
}

init?(value: [String: Any]) {
    guard let long = value["0"] as? Double,
        let lat = value["1"] as? Double else {return nil}
    self.long = long
    self.lat = lat
    self.address = value["name"] as? String
    self.visibility = value["visibility"] as? Bool
   }
}

Answer 1

让我带您了解一些可能有帮助的代码。这不是整个班级，而是所有的概念都在那里。我也在使用简化的 Firebase 结构，但同样，概念是相同的：

这是 Firebase 结构

users
  a_uid
    email: "some email"
    groups
      group_1: true
      group_2: true
    location
      coords: "[52.5, 67.1]"
      name: "Oyebanjo Solarin Street, Lagos"
      visibility: true
    username: "some username"

首先，似乎每个用户都有一个位置，这使它成为一个结构。

   struct LocationStruct {
        var coords: String?
        var name: String?
        var visibility: Bool?
    }

然后我们在用户类中使用该结构。在此示例中，我们为单个用户传入一个快照以初始化类并解构它以填充类变量。

class UserClass {
    var email = ""
    var username = ""
    var groupsDict: [String: Any]
    var loc = LocationStruct()

    init(snap: FIRDataSnapshot) {

        let userDict = snap.value as! [String: Any]

        self.email = userDict["email"] as! String
        self.username = userDict["username"] as! String

        self.groupsDict = userDict["groups"] as! [String: Any]

        let locationDict = userDict["location"] as! [String: Any]
        self.loc.coords = locationDict["coords"] as? String
        self.loc.name = locationDict["name"] as? String
        self.loc.visibility = locationDict["visibility"] as? Bool
    }
}

这是读取单个用户并填充 UserClass 的代码

    ref.child("users").child("a_uid")
                      .observeSingleEvent(of: .value, with: { snapshot in

        let user = UserClass(snap: snapshot)

        //this code is just to show the UserClass was populated.
        print(user.email)
        print(user.username)

        for group in user.groupsDict { //iterate over groups
            print(group)  //and print each one
        }

        print(user.loc.coords!) //print the location data
        print(user.loc.name!)
        print(user.loc.visibility!)
    })

您的结构中唯一剩下的问题是visibilityToSelectContacts 节点，该节点有一个子节点contacts。

因此，基本上 UserClass 中 userDict 的高级字典将有一个名为 visibilityToSelectContacts 的子级，然后有一个子级联系人，该子级联系人有一个键值对的子字典：“gFTCpzgSJDOsrVKWbAJp0Z1JFXp1”：true。像这样

userDict
   visibilityToSelectContacts
      contacts
        contant_0: true
        contant_1: true

我会让你把这个结构敲出来（提示：这是相同的设计模式）

Answer 2

尝试使用 3d 派对库进行拆箱，例如 this。
还要检查您用来提取未来孩子的密钥，例如：

LALocation(value: value["coordinates"] as? [String:Any] ?? [:])

这里你需要：

LALocation(value: value["location"] as? [String:Any] ?? [:])

获取数据后不要忘记提取对象 id snapshot.key