onSuccess 方法未在 android 中调用 firebase

Question

我正在尝试创建一个动态链接，当我尝试调试代码时，它正在调用回调方法 addOnSuccessListener 但之后它没有调用，或者我们说它正在跳过方法 onSuccess() 我不知道为什么它正在发生。

private void firebaseInvite() {
        FirebaseUser user = FirebaseAuth.getInstance().getCurrentUser();
        String uid = user.getUid();
        String url = "https://larky.funswitch.io/?invitedby=" + uid;
        FirebaseDynamicLinks.getInstance().createDynamicLink()
                .setLink(Uri.parse(url))
                .setDynamicLinkDomain("https://fmu3k.app.goo.gl")
                .setAndroidParameters(
                        new DynamicLink.AndroidParameters.Builder("io.funswitch.funrooster")
                                .setMinimumVersion(5)
                                .build())
                .buildShortDynamicLink()
                .addOnSuccessListener(shortDynamicLink -> {

在这之后我的调试器跳过了这段代码，它没有调用

 mInvitationUrl = shortDynamicLink.getShortLink();
                    mDatabase.child("Name").addListenerForSingleValueEvent(new ValueEventListener() {
                        @Override
                        public void onDataChange(@NonNull DataSnapshot dataSnapshot) {
                            String referrerName = dataSnapshot.getValue(String.class);
                            String subject = String.format("%s wants you to play MyExampleGame!", referrerName);
                            String invitationLink = mInvitationUrl.toString();
                            String msg = "Let's play MyExampleGame together! Use my referrer link: "
                                    + invitationLink;
                            String msgHtml = String.format("<p>Let's play MyExampleGame together! Use my "
                                    + "<a href=\"%s\">referrer link</a>!</p>", invitationLink);

                            Intent intent = new Intent(Intent.ACTION_SENDTO);
                            intent.setData(Uri.parse("mailto:")); // only email apps should handle this
                            intent.putExtra(Intent.EXTRA_SUBJECT, subject);
                            intent.putExtra(Intent.EXTRA_TEXT, msg);
                            intent.putExtra(Intent.EXTRA_HTML_TEXT, msgHtml);
                            if (intent.resolveActivity(getActivity().getPackageManager()) != null) {
                                startActivity(intent);
                            }
                        }

                        @Override
                        public void onCancelled(@NonNull DatabaseError databaseError) {

                        }
                    });

                });
    }

请帮帮我..

Answer 1

我得到它解决了这是一个非常基本的愚蠢错误我正在做的实际上链接没有在上面的代码中解析因为我在动态链接和动态链接域中提到了两次 https 在从动态链接域中删除 https 后我得到它的工作.

private void firebaseInvite() {
        FirebaseUser user = FirebaseAuth.getInstance().getCurrentUser();
        String uid = user.getUid();
        String url = "https://larky.funswitch.io/?invitedby=" + uid;
        FirebaseDynamicLinks.getInstance().createDynamicLink()
                .setLink(Uri.parse(url))
                .setDynamicLinkDomain("fmu3k.app.goo.gl")
                .setAndroidParameters(
                        new DynamicLink.AndroidParameters.Builder("io.funswitch.funrooster")
                                .setMinimumVersion(5)
                                .build())
                .buildShortDynamicLink()
                .addOnSuccessListener(shortDynamicLink -> {

 mInvitationUrl = shortDynamicLink.getShortLink();
                    mDatabase.child("Name").addListenerForSingleValueEvent(new ValueEventListener() {
                        @Override
                        public void onDataChange(@NonNull DataSnapshot dataSnapshot) {
                            String referrerName = dataSnapshot.getValue(String.class);
                            String subject = String.format("%s wants you to play MyExampleGame!", referrerName);
                            String invitationLink = mInvitationUrl.toString();
                            String msg = "Let's play MyExampleGame together! Use my referrer link: "
                                    + invitationLink;
                            String msgHtml = String.format("<p>Let's play MyExampleGame together! Use my "
                                    + "<a href=\"%s\">referrer link</a>!</p>", invitationLink);

                            Intent intent = new Intent(Intent.ACTION_SENDTO);
                            intent.setData(Uri.parse("mailto:")); // only email apps should handle this
                            intent.putExtra(Intent.EXTRA_SUBJECT, subject);
                            intent.putExtra(Intent.EXTRA_TEXT, msg);
                            intent.putExtra(Intent.EXTRA_HTML_TEXT, msgHtml);
                            if (intent.resolveActivity(getActivity().getPackageManager()) != null) {
                                startActivity(intent);
                            }
                        }

                        @Override
                        public void onCancelled(@NonNull DatabaseError databaseError) {

                        }
                    });

                });
    }