【发布时间】:2019-05-08 11:27:01
【问题描述】:
我正在学习 MVVM + RxSwift。 我想保存一个值以在下一个流程中重用它。 但是我遇到了上面的错误。
我假设我初始化了“translatedText”的值,但错误仍然出现。
我已经尝试了一些方法来初始化声明等等......
import UIKit
import RxSwift
final class ViewModel {
private let api: apiProtocol
let validationText: Observable<String>
let getObservable: Observable<String>
var translatedText: String
// var translatedText: String = "" //this case also dosn't work
init(inputObservable: Observable<String?>, changeButtonClicked: Observable<Void>, model: ModelProtocol, api: apiProtocol = APICntl()) {
self.api = api
self.translatedText = "" //I guess I initialised this here
let event = inputObservable
.flatMap { input -> Observable<Event<Void>> in
if let text = input {
self.translatedText = text // error. i want to save "input" to use at "let tapEvent"
}
return model
.validate(text: input)
.materialize()
}
.share()
self.validationText = event
.flatMap { event -> Observable<String> in
switch event {
case .next:
return .just("")
case let .error(error as ModelError):
return .just(error.errorLabel)
case .error, .completed:
return .empty()
}
}
.startWith(ModelError.invalidBlank.errorLabel)
let tapEvent = changeButtonClicked
.flatMap { (result) -> Observable<Event<String>> in
return api
.fetch(text: self.translatedText) // I want use it here
.materialize()
}
.share()
self.getObservable = tapEvent
.flatMap { event -> Observable<String> in
switch event {
case .next:
return .just(event.element!)
case let .error(error as ModelError):
return .just(error.errorLabel)
case .error, .completed:
return .empty()
}
}
}
}
你们有更好的解决方案吗?
-----自行解决-----
我只是在 let 事件之前创建了一个临时变量,它可以按我的意愿工作。
final class ViewModel {
private let api: apiProtocol
let validationText: Observable<String>
let getObservable: Observable<String>
init(inputObservable: Observable<String?>, changeButtonClicked: Observable<Void>, model: ModelProtocol, api: apiProtocol = APICntl()) {
self.api = api
var temp = ""
let event = inputObservable
.flatMap { input -> Observable<Event<Void>> in
if let text = input {
temp = text
}
return model
.validate(text: input)
.materialize()
}
.share()
【问题讨论】: