使用 objectForKey 返回错误类型的键

Question

• 我正在从 NSDictionary 数组的文件中读取数据。每个 NSDictionary 都包含一个名为“EnglishName”的键，一个值为 NSString 类型的值。我得到一个 NSDictionary 的值，用初始化函数创建新的 ViewController，比如：initWithName:[(NSDictionary*)oneObjectInArray objectForKey:@"EnglishName"];然后使用 NavigationController 推送它。
• 第一次推送->没问题。然后按回然后再做一次（单击以创建新的 ViewController 并推送）出现错误并通知：[__NSArrayM rangeOfString:]: unrecognized selector sent to instance 0x63509a0'。 -我通过添加命令 NSLog(@"%@", [object getObjectForKey:@"EnglishName"])->error 进行了检查。 然后我尝试在 didShowView 函数中再次读取数据（返回后）。它可以正常工作。

这是从文件中获取数据的代码。太长但可能有助于解决这个问题`- (void) getListStoriesAvailable { [_header removeAllObjects]; SAFE_RELEASE(saveDataFromDataFile) [storiesAvailableArray removeAllObjects]; NSString * 数字 = @"0123456789"; NSString * ALPHA = @"ABCDEFGHIJKLMNOPQRSTUVWXYZ";

for (int i = 0; i < 27; i++) 
{
    NSMutableArray * element = [[NSMutableArray alloc] init];
    [storiesAvailableArray addObject:element];
    [element release];
}
NSString * path = [NSString stringWithFormat: @"%@/data.ini",documentDirectory];
if ([[NSFileManager defaultManager] fileExistsAtPath:path]) 
{
    saveDataFromDataFile = [[NSMutableArray alloc] initWithContentsOfFile:path];
    for (int i = 0; i < [saveDataFromDataFile count]; i++)
        [[saveDataFromDataFile objectAtIndex:i] setObject:@"NO" forKey:@"Downloading"];
    for (int  i = 0; i < [saveDataFromDataFile count]; i++)
    {
        NSDictionary * theStory = [saveDataFromDataFile objectAtIndex:i];       
        NSString * word = [theStory objectForKey:@"EnglishName"];
        if ([word length] == 0) continue;

        NSString * firstCharacter = [[word substringToIndex: 1] uppercaseString];

        NSRange range;
        //The special case when the name of story start with a digit, add the story into "0-9" header and index
        range = [digit rangeOfString:firstCharacter];
        if (range.location != NSNotFound) 
        {
            [[storiesAvailableArray objectAtIndex:0] addObject:theStory];
            continue;
        }
        //Check the index of the first character
        range = [ALPHA rangeOfString:firstCharacter];
        if (range.location != NSNotFound) 
        {
            [[storiesAvailableArray objectAtIndex:(range.location + 1)] addObject:theStory];
            continue;
        }
    }
}
NSMutableArray * temp = [[NSMutableArray alloc] init];
for (int i = 0; i < [storiesAvailableArray count]; i++)
{
    if ([[storiesAvailableArray objectAtIndex:i] count] != 0)
    {
        [_header addObject:[ALPHA_ARRAY objectAtIndex:i]];
        [temp addObject:[storiesAvailableArray objectAtIndex:i]];
    }
}
[storiesAvailableArray removeAllObjects];
for (int i = 0; i < [temp count]; i++)
    [storiesAvailableArray addObject:[temp objectAtIndex:i]];
//storiesAvailableArray = temp;
[temp release];

} `

还有获取NSDictionary的代码

- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath 

{ 当前表 = 表视图； [tableView deselectRowAtIndexPath:indexPath 动画：YES]; NSInteger 行 = [indexPath 行]; NSDictionary * 故事； if (tableView == listStoriesAvailable) story = [[storiesAvailableArray objectAtIndex:[indexPath section]] objectAtIndex:row];

_storyDetail = [[StoryViewController alloc] initWithName:[story objectForKey:@"EnglishName"]];
[self.navigationController setDelegate:self];
[self.navigationController pushViewController:_storyDetail animated:YES];

}

那么问题是什么？请帮忙！

Answer 1

你没有保留你的字典。

请编辑您的问题并添加创建您的 NSDictionary 的代码。