【问题标题】:(iOS + Firebase) Unable to pass the Image to the next ViewController from a UITableViewCell(iOS + Firebase)无法将图像从 UITableViewCell 传递给下一个 ViewController
【发布时间】:2018-12-05 08:30:27
【问题描述】:

我有一个UITableView,其中的数据来自 Firebase RealtimeDatabase。一旦用户选择了行,行中的数据,即:标题、描述和图像将被带到下一个 ViewController。

我可以传递标题和描述,但我无法传递图片。

这是我的 UITableView 代码:

import UIKit
import Firebase

class PostTable: UIViewController, UITableViewDelegate, UITableViewDataSource {

    var tableView:UITableView!

    var posts = [Post]()

    override func viewDidLoad() {
        super.viewDidLoad()

        tableView = UITableView(frame: view.bounds, style: .plain)
        view.addSubview(tableView)

        let cellNib = UINib(nibName: "PostTableViewCell", bundle: nil)
        tableView.register(cellNib, forCellReuseIdentifier: "postCell")
        var layoutGuide:UILayoutGuide!

        layoutGuide = view.safeAreaLayoutGuide

        tableView.leadingAnchor.constraint(equalTo: layoutGuide.leadingAnchor).isActive = true
        tableView.topAnchor.constraint(equalTo: layoutGuide.topAnchor).isActive = true
        tableView.trailingAnchor.constraint(equalTo: layoutGuide.trailingAnchor).isActive = true
        tableView.bottomAnchor.constraint(equalTo: layoutGuide.bottomAnchor).isActive = true

        tableView.delegate = self
        tableView.dataSource = self
        tableView.tableFooterView = UIView()
        tableView.reloadData()


        observePosts()
    }

    override func didReceiveMemoryWarning() {
        super.didReceiveMemoryWarning()
        // Dispose of any resources that can be recreated.
    }

    func observePosts() {
        let postsRef = Database.database().reference().child("Data")
        print(postsRef)
        postsRef.observe(.value, with: { snapshot in
            var tempPosts = [Post]()

            for child in snapshot.children{

                if let childSnapshot = child as? DataSnapshot,
                    let dict = childSnapshot.value as? [String:Any],
                    let title = dict["title"] as? String,
                    let logoImage = dict["image"] as? String,
                    let url = URL(string:logoImage),
                    let description = dict["description"] as? String{


                    let userProfile = UserProfile(title: title, photoURL: url)
                    let post = Post(id: childSnapshot.key, title: userProfile, description: description, image: userProfile)
                    print(post)
                    tempPosts.append(post)
                }
            }

            self.posts = tempPosts
            self.tableView.reloadData()
        })
    }

    func getImage(url: String, completion: @escaping (UIImage?) -> ()) {
        URLSession.shared.dataTask(with: URL(string: url)!) { data, response, error in
            if error == nil {
                completion(UIImage(data: data!))
            } else {
                completion(nil)
            }
            }.resume()
    }

    func numberOfSections(in tableView: UITableView) -> Int {
        return 1
    }

    func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
        print(posts.count)
        return posts.count
    }

    func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell{
        let cell = tableView.dequeueReusableCell(withIdentifier: "postCell", for: indexPath) as! PostTableViewCell
        cell.set(post: posts[indexPath.row])
        return cell
    }

    func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) {
        let postsInfo = posts[indexPath.row]
        print(postsInfo)

        let Storyboard = UIStoryboard(name: "Main", bundle: nil)
        let DvC = Storyboard.instantiateViewController(withIdentifier: "PostTableDetailed") as! PostTableDetailed
        DvC.getName = postsInfo.title.title
        DvC.getDesc = postsInfo.description
//        DvC.getImg = postsInfo.title.photoURL
        self.navigationController?.pushViewController(DvC, animated: true)
    }
}

这是第二个 ViewControler,其中包含帖子详细信息:

import UIKit

class PostTableDetailed: UIViewController {

    var getName = String()
    var getDesc = String()

    @IBOutlet weak var Name: UILabel!
    @IBOutlet weak var Description: UILabel!

    override func viewDidLoad() {
        super.viewDidLoad()

        Name.text! = getName
        Description.text! = getDesc     
    }

    override func didReceiveMemoryWarning() {
        super.didReceiveMemoryWarning()
        // Dispose of any resources that can be recreated.
    }

}

我还有一些模型(Post、UserProfile)和服务(UserService 和 ImageService),如果需要解决这个问题,请告诉我。

【问题讨论】:

  • 你想要直接传递 UIImage 还是只传递 url??
  • 我希望UIImage能显示在下一个ViewController中,所以有效率的就行
  • 您可以像在 getName 和 getDesc 中一样在 PostTableDetailed 中简单地传递您的 url,并在 PostTableDetailed 中使用 getImage(url: String..) 方法
  • 或者看我的回答

标签: ios swift firebase uitableview


【解决方案1】:

如果您有 imageUrl,您只需将其从 PostTable 传递到 PostTableDetailed 并下载图像。

   // PostTable
       func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) {
            let postsInfo = posts[indexPath.row]
            print(postsInfo)

            let Storyboard = UIStoryboard(name: "Main", bundle: nil)
            let DvC = Storyboard.instantiateViewController(withIdentifier: "PostTableDetailed") as! PostTableDetailed
            DvC.getName = postsInfo.title.title
            DvC.getDesc = postsInfo.description
            DvC.getImg = postsInfo.photoURL
            self.navigationController?.pushViewController(DvC, animated: true)
        }

// PostTableDetailed
class PostTableDetailed: UIViewController {

    var getName = String()
    var getDesc = String()
    var imageUrl = ""

    @IBOutlet weak var Name: UILabel!
    @IBOutlet weak var Description: UILabel!
    @IBOutlet weak var imageView: UIImageView!


    override func viewDidLoad() {
        super.viewDidLoad()

        Name.text! = getName
        Description.text! = getDesc 
        updayeImage()    
    }

    override func didReceiveMemoryWarning() {
        super.didReceiveMemoryWarning()
        // Dispose of any resources that can be recreated.
    }

 private func updateImage() {
        URLSession.shared.dataTask(with: URL(string: self.imageUrl)!) { data, response, error in
            if error == nil, let data = data {
                imageView.image = UIImage(data: data)
            } 
            }.resume()
    }

}

任务完成时将显示图像。 所以我建议你为 imageView 添加一个微调器。

【讨论】:

  • 尝试在updateImage中绑定图片时出现此错误,Cannot assign value of type 'Data?' to type 'UIImage?'
  • 试试 UIImage(data: data),别忘了解包数据
【解决方案2】:

在 PostDetail ViewController 中这样做

import UIKit

class PostTableDetailed: UIViewController {

    var getName = String()
    var getDesc = String()
    var getImg = String()

    @IBOutlet weak var Name: UILabel!
    @IBOutlet weak var Description: UILabel!
    @IBOutlet weak var ImageContainer: UIImageView!

    override func viewDidLoad() {
        super.viewDidLoad()

        Name.text! = getName
        Description.text! = getDesc    
        if let image = getImage(url: getImg) { (image)
            ImageContainer.image = image 
        }

    }

    override func didReceiveMemoryWarning() {
         super.didReceiveMemoryWarning()
         // Dispose of any resources that can be recreated.
    }

    func getImage(url: String, completion: @escaping (UIImage?) -> ()) {
        URLSession.shared.dataTask(with: URL(string: url)!) { data, response, error in
            if error == nil {
                completion(UIImage(data: data!))
            } else {
                completion(nil)
            }
        }.resume()
    }

}

【讨论】:

    【解决方案3】:

    首先,您可以使用此代码下载图像:

    let imageCache = NSCache<AnyObject, AnyObject>()
    
    extension UIImageView {
    
    func downloadImageWithUrlString(urlString: String) -> Void {
    
        if urlString.count == 0 {
            print("Image Url is not found")
            return
        }
    
        self.image = nil
        if let cachedImage = imageCache.object(forKey: urlString as AnyObject) as? UIImage {
            self.image = cachedImage
            return
        }
    
        let request = URLRequest(url: URL(string: urlString)!)
        let dataTask = URLSession.shared.dataTask(with: request) {data, response, error in
            if error != nil { return }
            DispatchQueue.main.async {
                let downloadedImage = UIImage(data: data!)
                if let image = downloadedImage {
                    imageCache.setObject(image, forKey: urlString as AnyObject)
                    self.image = UIImage(data: data!)
                }
            }
        }
        dataTask.resume()
    }
    }
    

    现在,如果您正在使用包含 Title、Description 和 ImageUrlString 的模型,那么只需将选定的模型对象传递给下一个 viewController。

    在下一个 ViewController 中,只需调用相同的方法来下载您在第一个 ViewController 上使用的图像。您不需要将图像从 VC1 传递到 VC2,因为可能图像尚未下载,您选择了一行以移动到下一个 VC。

    所以这里简单的事情就是传递模型对象并调用图像下载方法。

    【讨论】:

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