字典数组中的字典 - Objective-C 中的逻辑挑战

Question

目标是将字典数组转换为一个包含不同对象的字典。我该怎么做？

我有一个这种格式的记录数组，

originalArray = [{
        "valid": "Y",
        "mof": "ON",
        "dof": "17-05-2019",
        "rtntype": "CODE1",
        "ret_prd": "042019",
    },
    {
        "valid": "Y",
        "mof": "ON",
        "dof": "19-04-2019",
        "rtntype": "CODE1",
        "ret_prd": "032019",
    },
    {
        "valid": "Y",
        "mof": "ON",
        "dof": "19-04-2019",
        "rtntype": "CODE2",
        "ret_prd": "032019",
    }
]

我想创建一个以下格式的字典。

{
    "032019" = {
        "CODE1" = {
            "valid": "Y",
            "mof": "ON",
            "dof": "19-04-2019",
            "rtntype": "CODE1",
            "ret_prd": "032019",
            },
        "CODE2" = {
            "valid": "Y",
            "mof": "ON",
            "dof": "19-04-2019",
            "rtntype": "CODE2",
            "ret_prd": "032019",
            "status": "Filed"
        }
    },
    "042019" =  {
        "CODE1" = {
            "valid": "Y",
            "mof": "ON",
            "dof": "17-05-2019",
            "rtntype": "CODE1",
            "ret_prd": "042019",
        }
    }
}

Answer 1

这是我的示例，你可以自己查看

NSArray *array = @[
    @{@"valid":@"Y",@"mof":@"ON",@"dof":@"17-05-2019",@"rtntype":@"CODE1",@"ret_prd":@"042019"},
    @{@"valid":@"Y",@"mof":@"ON",@"dof":@"19-04-2019",@"rtntype":@"CODE1",@"ret_prd":@"032019"},
    @{@"valid":@"Y",@"mof":@"ON",@"dof":@"19-04-2019",@"rtntype":@"CODE2",@"ret_prd":@"032019"}
];

NSMutableDictionary *result = [NSMutableDictionary new];
    for (int i = 0; i < array.count; i++) {
        NSDictionary *dict = array[i];
        NSString *value = dict[@"ret_prd"];
        if (result[value] == nil) {
            NSArray *filterArray = [array filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"(ret_prd contains[c] %@)", value]];
            NSMutableDictionary *filterDict = [NSMutableDictionary new];
            for (int i = 0; i < filterArray.count; i++) {
                filterDict[filterArray[i][@"rtntype"]] = filterArray[i];
            }
            result[value] = filterDict;
        }
    }

NSLog(@"%@", result);

控制台日志中的结果：

很久没有编写 Objective-C 代码了，所以上面的代码可能很奇怪。如果您不知道在哪里，请告诉我，我会为您解释。