您可以使用hierarchical 查询来生成每日数据。
SQL Fiddle
查询:
select
r_id,
i_id,
metric,
ctype,
timespan,
quantity,
tdate + level - 1 as m_tdate,
level as m_level,
(case ctype
when 'C' then
(case level
when 1 then 0.3
when 2 then 0.1
when 3 then 0.1
when 4 then 0.05
when 5 then 0.1
when 6 then 0.15
when 7 then 0.2
end)
else 1
end) * quantity as m_quantity
from myt
where timespan = 'Week'
connect by level <= 7
and r_id = prior r_id
and i_id = prior i_id
and metric = prior metric
and ctype = prior ctype
and timespan = prior timespan
and prior sys_guid() is not null
这将为每条记录生成 7 天的数据
Results:
| R_ID | I_ID | METRIC | CTYPE | TIMESPAN | QUANTITY | M_TDATE | M_LEVEL | M_QUANTITY |
|------|------|--------|-------|----------|----------|-----------------------|---------|------------|
| 1 | 1 | I | D | Week | 80 | May, 04 2015 00:00:00 | 1 | 80 |
| 1 | 1 | I | D | Week | 80 | May, 05 2015 00:00:00 | 2 | 80 |
| 1 | 1 | I | D | Week | 80 | May, 06 2015 00:00:00 | 3 | 80 |
| 1 | 1 | I | D | Week | 80 | May, 07 2015 00:00:00 | 4 | 80 |
| 1 | 1 | I | D | Week | 80 | May, 08 2015 00:00:00 | 5 | 80 |
| 1 | 1 | I | D | Week | 80 | May, 09 2015 00:00:00 | 6 | 80 |
| 1 | 1 | I | D | Week | 80 | May, 10 2015 00:00:00 | 7 | 80 |
| 1 | 1 | Q | C | Week | 200 | May, 04 2015 00:00:00 | 1 | 60 |
| 1 | 1 | Q | C | Week | 200 | May, 05 2015 00:00:00 | 2 | 20 |
| 1 | 1 | Q | C | Week | 200 | May, 06 2015 00:00:00 | 3 | 20 |
| 1 | 1 | Q | C | Week | 200 | May, 07 2015 00:00:00 | 4 | 10 |
| 1 | 1 | Q | C | Week | 200 | May, 08 2015 00:00:00 | 5 | 20 |
| 1 | 1 | Q | C | Week | 200 | May, 09 2015 00:00:00 | 6 | 30 |
| 1 | 1 | Q | C | Week | 200 | May, 10 2015 00:00:00 | 7 | 40 |
| 1 | 1 | S | C | Week | 100 | May, 04 2015 00:00:00 | 1 | 30 |
| 1 | 1 | S | C | Week | 100 | May, 05 2015 00:00:00 | 2 | 10 |
| 1 | 1 | S | C | Week | 100 | May, 06 2015 00:00:00 | 3 | 10 |
| 1 | 1 | S | C | Week | 100 | May, 07 2015 00:00:00 | 4 | 5 |
| 1 | 1 | S | C | Week | 100 | May, 08 2015 00:00:00 | 5 | 10 |
| 1 | 1 | S | C | Week | 100 | May, 09 2015 00:00:00 | 6 | 15 |
| 1 | 1 | S | C | Week | 100 | May, 10 2015 00:00:00 | 7 | 20 |
| 1 | 2 | I | D | Week | 50 | May, 04 2015 00:00:00 | 1 | 50 |
| 1 | 2 | I | D | Week | 50 | May, 05 2015 00:00:00 | 2 | 50 |
| 1 | 2 | I | D | Week | 50 | May, 06 2015 00:00:00 | 3 | 50 |
| 1 | 2 | I | D | Week | 50 | May, 07 2015 00:00:00 | 4 | 50 |
| 1 | 2 | I | D | Week | 50 | May, 08 2015 00:00:00 | 5 | 50 |
| 1 | 2 | I | D | Week | 50 | May, 09 2015 00:00:00 | 6 | 50 |
| 1 | 2 | I | D | Week | 50 | May, 10 2015 00:00:00 | 7 | 50 |
| 1 | 2 | Q | C | Week | 100 | May, 04 2015 00:00:00 | 1 | 30 |
| 1 | 2 | Q | C | Week | 100 | May, 05 2015 00:00:00 | 2 | 10 |
| 1 | 2 | Q | C | Week | 100 | May, 06 2015 00:00:00 | 3 | 10 |
| 1 | 2 | Q | C | Week | 100 | May, 07 2015 00:00:00 | 4 | 5 |
| 1 | 2 | Q | C | Week | 100 | May, 08 2015 00:00:00 | 5 | 10 |
| 1 | 2 | Q | C | Week | 100 | May, 09 2015 00:00:00 | 6 | 15 |
| 1 | 2 | Q | C | Week | 100 | May, 10 2015 00:00:00 | 7 | 20 |
| 1 | 2 | S | C | Week | 150 | May, 04 2015 00:00:00 | 1 | 45 |
| 1 | 2 | S | C | Week | 150 | May, 05 2015 00:00:00 | 2 | 15 |
| 1 | 2 | S | C | Week | 150 | May, 06 2015 00:00:00 | 3 | 15 |
| 1 | 2 | S | C | Week | 150 | May, 07 2015 00:00:00 | 4 | 7.5 |
| 1 | 2 | S | C | Week | 150 | May, 08 2015 00:00:00 | 5 | 15 |
| 1 | 2 | S | C | Week | 150 | May, 09 2015 00:00:00 | 6 | 22.5 |
| 1 | 2 | S | C | Week | 150 | May, 10 2015 00:00:00 | 7 | 30 |
一旦你有了这个,你需要旋转结果,这可以通过简单的 GROUP BY 来完成
查询:
with x as (
select
r_id,
i_id,
metric,
ctype,
timespan,
quantity,
tdate + level - 1 as m_tdate,
level as m_level,
(case ctype
when 'C' then
(case level
when 1 then 0.3
when 2 then 0.1
when 3 then 0.1
when 4 then 0.05
when 5 then 0.1
when 6 then 0.15
when 7 then 0.2
end)
else 1
end) * quantity as m_quantity
from myt
where timespan = 'Week'
connect by level <= 7
and r_id = prior r_id
and i_id = prior i_id
and metric = prior metric
and ctype = prior ctype
and timespan = prior timespan
and prior sys_guid() is not null
UNION ALL
select
r_id,
i_id,
metric,
ctype,
timespan,
quantity,
tdate as m_tdate,
1 as m_level,
quantity as m_quantity
from myt
where timespan = 'Day'
)
select
r_id,
i_id,
m_tdate,
sum(case when metric = 'S' then m_quantity end) S,
sum(case when metric = 'Q' then m_quantity end) Q,
sum(case when metric = 'I' then m_quantity end) I
from x
group by
r_id,
i_id,
m_tdate
order by
r_id,
i_id,
m_tdate
Results:
| R_ID | I_ID | M_TDATE | S | Q | I |
|------|------|-------------------------|--------|--------|-----|
| 1 | 1 | May, 04 2015 00:00:00 | 30 | 60 | 80 |
| 1 | 1 | May, 05 2015 00:00:00 | 10 | 20 | 80 |
| 1 | 1 | May, 06 2015 00:00:00 | 10 | 20 | 80 |
| 1 | 1 | May, 07 2015 00:00:00 | 5 | 10 | 80 |
| 1 | 1 | May, 08 2015 00:00:00 | 10 | 20 | 80 |
| 1 | 1 | May, 09 2015 00:00:00 | 15 | 30 | 80 |
| 1 | 1 | May, 10 2015 00:00:00 | 20 | 40 | 80 |
| 1 | 2 | April, 03 2015 00:00:00 | (null) | (null) | 120 |
| 1 | 2 | May, 04 2015 00:00:00 | 45 | 30 | 50 |
| 1 | 2 | May, 05 2015 00:00:00 | 15 | 10 | 50 |
| 1 | 2 | May, 06 2015 00:00:00 | 15 | 10 | 50 |
| 1 | 2 | May, 07 2015 00:00:00 | 7.5 | 5 | 50 |
| 1 | 2 | May, 08 2015 00:00:00 | 15 | 10 | 50 |
| 1 | 2 | May, 09 2015 00:00:00 | 22.5 | 15 | 50 |
| 1 | 2 | May, 10 2015 00:00:00 | 30 | 20 | 50 |