【发布时间】:2014-11-16 00:00:49
【问题描述】:
我正在为自己制作一个应用程序,以查看我大学的课程(已满)何时可用。
我需要我的应用程序能够以编程方式将信息输入“类搜索”表单并按下提交按钮,以便我可以检查是否有任何打开的类出现。
这里是表格的网址:https://css.nevada.unr.edu/psc/rncssprd/EMPLOYEE/HRMS/c/COMMUNITY_ACCESS.CLASS_SEARCH.GBL
到目前为止,我可以在表单中输入数据并在 web 视图中看到它的显示。问题是当我让程序单击提交按钮时没有任何反应。好吧,实际上它确实会搜索,但是我之前提交的数据会丢失,并且它在表单中没有值进行搜索。
这是我目前的代码:
public class Main extends Activity{
String URL = "https://css.nevada.unr.edu/psc/rncssprd/EMPLOYEE/HRMS/c/COMMUNITY_ACCESS.CLASS_SEARCH.GBL";
WebView mWebview;
int noRepeat = 0;
@Override
protected void onCreate(Bundle savedInstanceState) {
// TODO Auto-generated method stub
super.onCreate(savedInstanceState);
new FetchItemsTask().execute();
}
private class FetchItemsTask extends AsyncTask<Void,Void,Boolean> {
@Override
protected void onPreExecute() {
}
@Override
protected Boolean doInBackground(Void... params) {
// TODO Auto-generated method stub
return true;
}
@Override
protected void onPostExecute(Boolean result) {
// TODO Auto-generated method stub
super.onPostExecute(result);
mWebview = (WebView ) findViewById(R.id.webView1);
// load login url
mWebview.loadUrl(URL);
//mWebview.setVisibility(View.INVISIBLE);
mWebview.getSettings().setJavaScriptEnabled(true);
mWebview.setWebViewClient(new WebViewClient() {
public void onPageFinished(WebView view, String url) {
// first time go to search page
Toast.makeText(getApplicationContext(), "done loading login, pressing button", Toast.LENGTH_SHORT).show();
mWebview.loadUrl("javascript: {" + "document.getElementById('SSR_CLSRCH_WRK_SUBJECT$0').value = '"+"temp1"+"';" +
"document.getElementById('SSR_CLSRCH_WRK_CATALOG_NBR$1').value = '"+"temp2"+"';" +
"document.getElementsByName('CLASS_SRCH_WRK2_SSR_PB_CLASS_SRCH')[0].click();" +
"};" ); // if I take out the click here the form will have temp1 and temp2 entered and everything fine, but it clicks temp1 and temp2 get cleared before it clicks some reason
}
});
}
}
感谢您的帮助,我很感激。如果您还需要查看该表单所在的网站。
【问题讨论】:
标签: javascript android forms webview programmatically-created