【问题标题】:Changing samplerate and byterate of a wav file without encountering problems opening the file?更改 wav 文件的采样率和比特率而不会遇到打开文件的问题?
【发布时间】:2015-07-12 21:34:33
【问题描述】:

我正在尝试将 503,196 字节的 wav 文件的内容写入另一个文件,并将采样率/字节率加倍以使速度加倍。但是,我无法从输入文件中读取数据并将其写入输出文件。这是我的代码:

#include <stdio.h>

int main() {
    struct WAVE {
           char ChunkID[4];
           unsigned int ChunkSize;
           char Format[4];
           char Subchunk1ID[4];
           unsigned int Subchunk1Size;
           unsigned short int AudioFormat;
           unsigned short int NumChannels;
           unsigned int SampleRate;
           unsigned int ByteRate;
           unsigned short int BlockAlign;
           unsigned short int BitsPerSample;
           char Subchunk2ID[4];
           unsigned int Subchunk2Size;
    } wav;
    FILE *original, *fast;
    original = fopen("Alejandro_project.wav", "rb");
    fast = fopen("Alejandro_fast.wav", "wb");
    if (original == NULL) {
                 printf("File does not exist.\n");
                 return 0;
    }
    fread(&wav, 1, 44, original);
    unsigned short int data[12 * wav.SampleRate]
    int i;
    for (i = 0; i < Subchunk2Size / 2; i++)
        fread(&data[i], 1, 2, original);
    fwrite(&wav, 1, 44, fast);
    unsigned int fastSampleRate = wav.SampleRate * 2;
    unsigned int fastByteRate = 2 * fastSampleRate;
    fseek(fast, 24, SEEK_SET);
    fwrite(&fastSampleRate, 4, 1, fast);
    fseek(fast, 28, SEEK_SET);
    fwrite(&fastByteRate, 4, 1, fast);
    fwrite(data, 1, 2, original);
    fclose(fast);
    fclose(original);
}

【问题讨论】:

  • 您可能应该打包您的 WAVE 结构(#pragma pack(1)__attribute__((__packed__)) 或其他)...它可能有不需要的填充。
  • 程序启动时 Alejandro_fast.wav 是否已经包含该文件的副本?看起来您没有将标头之后的其余文件写入目标文件
  • @samgak 实际上,既然你提到了它,即使 Alejandro_fast.wav 确实 (最初)包含一个副本,它也会被丢弃,因为文件是用 " wb"...也许"r+b"会更好。

标签: c audio wav alter tweak


【解决方案1】:

有几个问题.. 对于初学者,您需要确保 WAVE 标头的结构已打包,以免结构内出现意外填充,从而导致某些字段未对齐并增加结构的大小.否则,您可能会在每个 unsigned short int 成员之后获得两个字节的额外填充。

#pragma pack(push,1) /* for VC, may also work for GCC */
struct WAVE {
     /* ...struct contents... */
} wav;
#pragma pack(pop)

其次,您似乎正试图简单地覆盖新文件中的 SampleRate 和 ByteRate 成员,而其余部分保持不变。这仅在新文件已经是旧文件的副本时才有效。如果是这样,您还需要将打开新文件的模式更改为“r+b”(读取模式+写入)而不是“wb”(写入模式),这样现有文件内容就不会被丢弃。

当您尝试写入标头时也会出错。这一行:

fread(original, 1, 44, fast);

应该是:

fwrite(&wav, 44, 1, fast);

将 44 个字节从 wav 写入新文件,而不是从新文件中读取并使用旧文件的 FILE * 作为目标。


如果新文件不是已经是旧文件的副本,您还需要复制文件的其余部分(包括标题的其他部分)。在这种情况下,这可能是最简单的(一旦打开文件):

  1. 将旧文件的标头读入wav

    fread(&wav, sizeof(wav), 1, original);
    
  2. 修改SampleRateByteRate 字段

    wav.SampleRate *= 2;
    wav.ByteRate *= 2;
    
  3. 将整个修改后的wav标头写入新文件

    fwrite(&wav, sizeof(wav), 1, fast);
    
  4. 循环复制旧文件的剩余部分到新文件中

    char buf[1024];
    int count;
    while ((count = fread(buf, 1, sizeof(buf), original)) > 0)
        fwrite(buf, 1, count, fast);
    

..然后关闭文件并返回。

【讨论】:

    【解决方案2】:

    我想通了。我删除了结构只是为了看看我在做什么。完成最终项目后,我将重新合并该结构。

    #include <stdio.h>
    #include <stdlib.h>
    #include <string.h>
    
    int main() {
        FILE *original, *fast, *slow, *slowdown;
        unsigned int ChunkSize, Subchunk1Size, Subchunk2Size, RIFFSize, fmtSize, dataSize, SampleRate, ByteRate;
        unsigned short int AudioFormat, NumChannels, BlockAlign, BitsPerSample;
        char ChunkID[5], Format[5], Subchunk1ID[5], Subchunk2ID[5];
        ChunkID[4] = '\0';
        Format[4] = '\0';
        Subchunk1ID[4] = '\0';
        Subchunk2ID[4] = '\0';
        char path[FILENAME_MAX], dfast[FILENAME_MAX], dslow[FILENAME_MAX], dslowdown[FILENAME_MAX];
        printf("Enter path to Alejandro_project.wav file: ");
        scanf("%s", path);
        strcpy(dfast, path);
        dfast[strlen(path) - 21] = '\0';
        strcpy(dslow, dfast);
        strcpy(dslowdown, dslow);
        strcat(dfast, "Alejandro_fast.wav");
        strcat(dslow, "Alejandro_slow.wav");
        strcat(dslowdown, "Alejandro_slowdown.wav");
        original = fopen(path, "rb");
        if (!original) {
            printf("Error: file does not exist.\n");
            return EXIT_FAILURE;
        }
        fread(ChunkID, 4, 1, original);
        fread(&ChunkSize, 4, 1, original);
        fread(Format, 4, 1, original);
        fread(Subchunk1ID, 4, 1, original);
        fread(&Subchunk1Size, 4, 1, original);
        fread(&AudioFormat, 2, 1, original);
        fread(&NumChannels, 2, 1, original);
        fread(&SampleRate, 4, 1, original);
        fread(&ByteRate, 4, 1, original);
        fread(&BlockAlign, 2, 1, original);
        fread(&BitsPerSample, 2, 1, original);
        fread(Subchunk2ID, 4, 1, original);
        fread(&Subchunk2Size, 4, 1, original);
        fmtSize = Subchunk1Size + 8;
        dataSize = Subchunk2Size + 8;
        RIFFSize = ChunkSize + 8 - (fmtSize + dataSize);
        printf("RIFF Size:     %d\n", RIFFSize);
        printf("fmt Size:      %d\n", fmtSize);
        printf("data Size:     %d\n\n", dataSize);
        printf("ChunkID:       %s\n", ChunkID);
        printf("ChunkSize:     %d\n", ChunkSize);
        printf("Format:        %s\n\n", Format);
        printf("Subchunk1ID:   %s\n", Subchunk1ID);
        printf("Subchunk1Size: %d\n", Subchunk1Size);
        printf("AudioFormat:   %d\n", AudioFormat);
        printf("NumChannels:   %d\n", NumChannels);
        printf("SampleRate:    %d\n", SampleRate);
        printf("ByteRate:      %d\n", ByteRate);
        printf("BlockAlign:    %d\n", BlockAlign);
        printf("BitsPerSample: %d\n\n", BitsPerSample);
        printf("Subchunk2ID:   %s\n", Subchunk2ID);
        printf("Subchunk2Size: %d\n", Subchunk2Size);
        fseek(original, 0, SEEK_SET);
        fast = fopen(dfast, "wb");
        unsigned int fastSampleRate = SampleRate * 2;
        unsigned int fastByteRate = 2 * fastSampleRate;
        fwrite(ChunkID, 4, 1, fast);
        fwrite(&ChunkSize, 4, 1, fast);
        fwrite(Format, 4, 1, fast);
        fwrite(Subchunk1ID, 4, 1, fast);
        fwrite(&Subchunk1Size, 4, 1, fast);
        fwrite(&AudioFormat, 2, 1, fast);
        fwrite(&NumChannels, 2, 1, fast);
        fwrite(&fastSampleRate, 4, 1, fast);
        fwrite(&fastByteRate, 4, 1, fast);
        fwrite(&BlockAlign, 2, 1, fast);
        fwrite(&BitsPerSample, 2, 1, fast);
        fwrite(Subchunk2ID, 4, 1, fast);
        fwrite(&Subchunk2Size, 4, 1, fast);
        short int data;
        unsigned int i;
        for (i = 0; i < Subchunk2Size / 2; i++) {
            fread(&data, 2, 1, original);
            fwrite(&data, 2, 1, fast);
        }
        fclose(fast);
        fseek(original, 0, SEEK_SET);
        slow = fopen(dslow, "wb");
        unsigned int slowSampleRate = SampleRate / 2;
        unsigned int slowByteRate = 2 * slowSampleRate;
        fwrite(ChunkID, 4, 1, slow);
        fwrite(&ChunkSize, 4, 1, slow);
        fwrite(Format, 4, 1, slow);
        fwrite(Subchunk1ID, 4, 1, slow);
        fwrite(&Subchunk1Size, 4, 1, slow);
        fwrite(&AudioFormat, 2, 1, slow);
        fwrite(&NumChannels, 2, 1, slow);
        fwrite(&slowSampleRate, 4, 1, slow);
        fwrite(&slowByteRate, 4, 1, slow);
        fwrite(&BlockAlign, 2, 1, slow);
        fwrite(&BitsPerSample, 2, 1, slow);
        fwrite(Subchunk2ID, 4, 1, slow);
        fwrite(&Subchunk2Size, 4, 1, slow);
        for (i = 0; i < Subchunk2Size / 2; i++) {
            fread(&data, 2, 1, original);
            fwrite(&data, 2, 1, slow);
        }
        fclose(slow);    
        fclose(original);
        system("pause");
        return EXIT_SUCCESS;
    }
    

    【讨论】:

      【解决方案3】:

      要使速度加倍,您不能只更改 WAV 标头中的 sample ratebyte-rate。如果这样做,它会播放得很快,但由于音高错误而听起来很奇怪。相反,您需要使用适当的采样率转换 (SRC) 库将输入 WAV 文件转换为具有更快采样率的输出 WAV 文件。

      【讨论】:

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