【发布时间】:2019-07-22 03:15:10
【问题描述】:
我希望在一个场景中拥有多个 UIPickerView,而不会让我的视图控制器因委托功能而臃肿。我在 UIPickerViews 上看到的所有教程都建议使用视图控制器本身作为 UIPickerView 的委托。
如何将此委托代码移出ViewController?
受this tutorial 的启发,这里有一个视图控制器,它将自己作为委托分配给它的 UIPickerViews。我对用于将行为映射到每个 UIPickerView 的 if/else 逻辑持批评态度:
import UIKit
class ViewController: UIViewController, UIPickerViewDelegate, UIPickerViewDataSource {
@IBOutlet weak var pickerViewA: UIPickerView!
@IBOutlet weak var pickerViewB: UIPickerView!
let contentsA = ["1A", "2A", "3A"]
let contentsB = ["1B", "2B", "3B", "4B"]
override func viewDidLoad() {
super.viewDidLoad()
pickerViewA.delegate = self
pickerViewA.dataSource = self
pickerViewB.delegate = self
pickerViewB.dataSource = self
}
func numberOfComponents(in pickerView: UIPickerView) -> Int {
return 1 //Applies to both pickerViewA & pickerViewB
}
func pickerView(_ pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int {
if pickerView == pickerViewA {
return contentsA.count
} else {
return contentsB.count
}
}
func pickerView(_ pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String? {
if pickerView == pickerViewA {
return contentsA[row]
} else {
return contentsB[row]
}
}
func pickerView(_ pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int) {
if pickerView == pickerViewA {
// Do something A
} else {
// Do something B
}
}
}
理想情况下,我希望有一个符合这些协议的自定义类,然后为每个 UIPickerView 创建此类的新实例,以便它们具有唯一的委托和行为。
当我尝试定义一个名为“PickerDelegate”且符合 UIPickerViewDelegate 和 UIPickerViewDataSource 的单独类时,我在 Xcode 中收到此错误:
类型“PickerDelegate”不符合协议“NSObjectProtocol”
显然UIPickerViewDelegate & UIPickerViewDataSource 继承自NSObjectProtocol。如果我添加协议存根(如 Xcode 所建议的那样),我会得到一长串我并不热衷于实现的功能。
有没有更简单的方法在视图控制器之外符合这些协议?
【问题讨论】:
标签: ios swift uipickerview uipickerviewdatasource uipickerviewdelegate