【发布时间】:2014-03-19 04:47:29
【问题描述】:
NSMutableURLRequest *request=[NSMutableURLRequest requestWithURL:[NSURL URLWithString:@"http://advantixcrm.com/prj/mitech/index.php/api/appconfig/Mx"]];
[request setHTTPMethod:@"GET"];
[request setValue:@"application/json;charset=UTF-8" forHTTPHeaderField:@"content-type"];
NSError *err;
NSURLResponse *response;
NSData *responseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&err];
NSDictionary *jsonArray = [NSJSONSerialization JSONObjectWithData:responseData options: NSJSONReadingMutableContainers error: &err];
NSArray *array=[jsonArray objectForKey:@"RestInfo"];
for (int i=0; i<[array count]; i++) {
NSString*location=[[array objectAtIndex:i]objectForKey:@"restaurant_location"];
[data addObject:location];
- (NSInteger)numberOfComponentsInPickerView:(UIPickerView *)pickerView{
return 1;
}
- (NSInteger)pickerView:(UIPickerView *)pickerView numberOfRowsInComponent: (NSInteger)component{
switch (component) {
case 0:
return [data count];
break;
default:
return 0;
break;
}
return 0;
}
- (NSString *)pickerView:(UIPickerView *)pickerView titleForRow:(NSInteger)row forComponent:(NSInteger)component{
switch (component) {
case 0:
return [data objectAtIndex:row];
break;
default:
return 0;
break;
}
}
我想将我的 JSON 对象带到 UIPickerView,但我只得到“?”。
如何将我的数据带入 UIPickerView?
【问题讨论】:
-
请详细说明您的问题。
-
问题不清楚。您现在面临什么问题?
-
你在数据数组中得到了什么?
-
我想从 json 中获取对象 "restaurant_location" 以显示在 uipickerview 中
标签: ios iphone json xcode uipickerview