如何将 UIPickerview 值发布到 JSON url

Question

我有两个 UITextFields(cityNames,collageNames)。我获取 JSON url 的数据。我根据 UITextFields 获取并放置数据到 UIPickerview。 when select cityName that city name placed into UITextFields but now I need that particular index value post to JSON URL and same as collage name .我知道字符串值 Post to JSON url。但我不知道如何将UIPickerview 索引值发布到 JSON url。

- (void)pickerView:(UIPickerView *)pickerView didSelectRow:(NSInteger)row inComponent:(NSInteger)component
{
      NSLog(@"select row is %d",row);
    if(pickerView.tag==1){
     CityName.text = [secondArray objectAtIndex:row];

        string1=
        [NSString stringWithFormat:@"%d",[yourpicker selectedRowInComponent:0]];
        NSLog(@"string ring %@",string1);

           }
    else if(pickerView.tag==2){
     CollageName.text = [firstArray objectAtIndex:row];

        string2=
        [NSString stringWithFormat:@"%d",[yourpicker selectedRowInComponent:0]];

    }
}

String1 和 String2 是获取 IndexValue 。但我不知道如何将特定的 Stringvalue 传递给 JSON。我很累，但是当我使用 Did-select 方法的 NSLog outSide 打印字符串 1 和 2 时，它显示空值。当我打印Didselect 方法中的字符串值显示选择索引值

 NSString *post =[NSString stringWithFormat:@"?&citynames=%@&collageNames=%@",cityname.text,collagename.text];

或

 NSString *post =[NSString stringWithFormat:@"?&citynames=%@&collageNames=%@",string1,string2];


    NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];

    NSString *postLength = [NSString stringWithFormat:@"%d",[postData length]];

    NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init] ;

    [request setURL:[NSURL URLWithString:[NSString stringWithFormat:@"http://192.168.3.35:8090/SaveDollar/rest/users/add"]]];


    NSLog(@"getData%@",request);

    [request setHTTPMethod:@"POST"];

    [request setValue:postLength forHTTPHeaderField:@"Content-Length"];

    [request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Current-Type"];

    [request setHTTPBody:postData];

    NSLog(@"getData%@",request);


    con3 = [[NSURLConnection alloc]initWithRequest:request delegate:self];

    if(con3)
    {      webData3=[NSMutableData data];
        NSLog(@"Connection successfull");
        NSLog(@"GOOD Day My data %@",webData3);
    }
    else
    {
        NSLog(@"connection could not be made");
    }

我像这样累了（上面的代码）。我没有得到。所以请告诉我如何将UIPickerView indexValue 发布到 JSON 网址。

感谢高级。

Answer 1

您有两个不同的pickerViews，所以没问题。

从两个不同的数组中获取实际值：

    NSString *collegeName=[collegeArray objectAtIndex:[self.dataPicker1 selectedRowInComponent:0]];

或者：

如果您能够看到 textField 值，您也可以将它们用作：

NSString *collegeName=collegeTextField.text;

另一种获取索引的方法，即从 textField：

int index=[collegeNameArray indexOfObject:collegeName];

然后你可以将index 传递给你的urlString。

要获取 pickerView 选定的索引，请使用：

[self.dataPicker1 selectedRowInComponent:0]

您可以将 urlString 构建为：

urlString=[NSString stringWithFormat:@"?&citynames=%@&collageNames=%@",[self.dataPicker1 selectedRowInComponent:0],[self.dataPicker2 selectedRowInComponent:0]];