【问题标题】:How to run code based on UIPickerview selections?如何根据 UIPickerview 选择运行代码?
【发布时间】:2020-06-02 14:09:24
【问题描述】:

我正在制作一个类似于谷歌文档或其他文本编辑器的简单 iOS 应用程序。我创建了一个 UIPickerview 来更改字体大小,但后来我意识到当我选择某些东西时,什么也没有发生。那么有什么办法可以做到这一点,这是我的代码

import UIKit

class FirstViewController: UIViewController, UIPopoverPresentationControllerDelegate, UIPickerViewDelegate, UIPickerViewDataSource {


    @IBOutlet weak var fontBTN: UIButton!
    func numberOfComponents(in pickerView: UIPickerView) -> Int {
        return 1
    }
    func pickerView(_ pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int {
        return arrayFruits.count
    }
    func pickerView(_ pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String? {
        return arrayFruits[row]
    }
    func pickerView(_ pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int) {

    }
    var arrayFruits = [String]()
    @IBOutlet weak var picker: UIPickerView!
    @IBOutlet weak var aligners: UISegmentedControl!

    @IBOutlet weak var foramtters: UISegmentedControl!
    @IBOutlet weak var textView: UITextView!

    var pickerData = ["10", "12", "14", "16", "18", "20", "22", "24", "26", "28", "30", "36", "48", "72"]


    override func viewDidLoad() {
        super.viewDidLoad()
        // Do any additional setup after loading the view.
        self.picker.delegate = self
        self.picker.dataSource = self
        arrayFruits = ["10", "12", "14", "16", "18", "20", "22", "24", "26", "28", "30", "36", "48", "72"]
    }


    @IBAction func aligning(_ sender: Any) {
        switch aligners.selectedSegmentIndex {
        case 0:
            textView.textAlignment = .left
        case 1:
            textView.textAlignment = .center
        case 2:
            textView.textAlignment = .right
        case 3:
            textView.textAlignment = .justified
        default: break

        }
    }

    @IBAction func formating(_ sender: Any) {
        switch foramtters.selectedSegmentIndex {
        case 0:
            textView.font = UIFont.boldSystemFont(ofSize: 14)
        case 1:
            textView.attributedText = NSAttributedString(string: textView.text, attributes:
                [.underlineStyle: NSUnderlineStyle.single.rawValue])
            textView.font = UIFont(name: "Arial", size: 14)
        case 2:
            textView.font = UIFont.italicSystemFont(ofSize: 14)
        default: break

        }

    }

    @IBAction func fontPicker(_ sender: Any) {
        if picker.isHidden == true {
            picker.isHidden = false
            fontBTN.setTitle("Done", for: .normal)
        } else if picker.isHidden == false {
            fontBTN.setTitle("Aa", for: .normal)
            picker.isHidden = true

        }
    }


}

我尝试过Switch statement,但我收到错误消息"Expression pattern of type 'Int' cannot match values of type 'UIPickerView?'" 我尝试用谷歌搜索,但没有任何显示,所以我问了这个问题。

switch picker {
        case 0:
            //funtion here
        default:

        }

你能帮帮我吗?

【问题讨论】:

  • didSelectRow 的主体是空的,所以当您在选择器中选择项目时它什么也不做,将您想要的代码移到那里。
  • 我要在那里放一个 switch 语句吗?
  • 你到底想达到什么目的?
  • 更改文本视图的字体大小

标签: ios swift xcode uipickerview


【解决方案1】:

考虑以下代码:

class ViewController: UIViewController {
    @IBOutlet weak var picker: UIPickerView!

    @IBOutlet weak var textView: UITextView!
    let data: [CGFloat] = [20, 25, 30]

    override func viewDidLoad() {
        super.viewDidLoad()
        picker.delegate = self
        picker.dataSource = self
    }
}

extension ViewController: UIPickerViewDelegate {
    func pickerView(_ pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int) {
        textView.font = UIFont.systemFont(ofSize: data[row])
    }
}

extension ViewController: UIPickerViewDataSource {
    func numberOfComponents(in pickerView: UIPickerView) -> Int {
        return 1
    }

    func pickerView(_ pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int {
        return data.count
    }

    func pickerView(_ pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String? {
        return "\(data[row])"
    }
}

因此,您可以通过实现如上所示的 didSelectRow 方法来运行基于 UIPickerView 选择的代码。
编辑:
我已更改代码以更新 textView 的 fontSize。

【讨论】:

    【解决方案2】:

    要根据选择器选择更改 textView 的字体大小,您需要执行以下操作。

    func pickerView(_ pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int) {
          if let doubleValue = Double(arrayFruits[row]) {
              let fontSize = CGFloat(doubleValue)
              textView.font = UIFont.systemFont(ofSize: fontSize)
          }
    }
    

    【讨论】:

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