【发布时间】:2020-07-04 09:58:37
【问题描述】:
我想在 Xcode Swift 中创建一个类,请看这段代码:
class Cards {
var roundNumber = 10
var monsters:[
(Id: Int, Name:String, Description: String, Attack_min: Int, Attack_max: Int, Health: Int, VP: Int, Gold:Int)] = [
(Id: 1, Name: "Ice dragon", Description: "Attack on Wizards +1", Attack_min: 2, Attack_max: 5, Health: 4, VP: 2, Gold: 4),
(Id: 2, Name: "Fire dragon", Description: "Attack on Wariors +2", Attack_min: 2, Attack_max: 5, Health: 4, VP: 2, Gold: 4),
(Id: 3, Name: "Acid witch", Description: "Attack of all heroes -1 \n(Only -1 on heroes)", Attack_min: 3, Attack_max: 6, Health: 5, VP: 4, Gold: 5),
(Id: 4, Name: "Killer rats", Description: "Health -1 when attacked by supporting cards ", Attack_min: 2, Attack_max: 6, Health: 3, VP: 1, Gold: 3)
]
var monsterDeck = [Any]()
func randomizer(lowestNumber: Int, highestNumber: Int) -> Int {
return Int.random(in: lowestNumber ... highestNumber)
}
func round() {
if self.roundNumber == 10 {
self.monsters.shuffle()
self.monsterDeck = self.monsters
} else {
self.monsterDeck.removeFirst()
}
self.roundNumber -= 1
}
}
var cards = Cards()
cards.round()
print("\(cards.monsterDeck[0].Name)\n")
print(cards.monsterDeck)
print(cards.roundNumber)
var monsters 是一个数组,我要自己更新 我想洗牌并将其存储在 var monsterDeck
我想要的是,每次我运行函数 round() 时,我都想要一张洗牌的新怪物卡,并且应该移除第一个怪物卡组。
但在底部你会看到 print("\(cards.monsterDeck[0].Name)\n") 并且我得到一个错误:
error: MyPlayground.playground:34:31: error: value of type 'Any' has no member 'Name'
print("\(cards.monsterDeck[0].Name)\n")
那么我该如何解决这个问题?基本上我希望 var monsterDeck 是一个数组,它是数组怪物的洗牌版本
我检查了this article,但这些答案假设数组只是字符串或整数。
我的例子有字符串和整数字段
【问题讨论】:
标签: swift xcode swift-playground