使用 Alamofire 设置 HTTP Headers 和 HTTP Body

Question

我一直在使用 NSURLConnection 发出请求，我想将代码迁移到 Alamofire。

这是我的 NSURLConnection 代码。

var requestString: NSString = "http://api.domainname.com/api/v1/auth/register";
var url: NSURL = NSURL(string: requestString.stringByAddingPercentEscapesUsingEncoding(NSUTF8StringEncoding)!)!;

var urlRequest: NSMutableURLRequest = NSMutableURLRequest(URL: url);
urlRequest.setValue("\(base64LoginString)", forHTTPHeaderField: "Authorization");
urlRequest.setValue("application/json", forHTTPHeaderField: "Content-Type");
urlRequest.setValue("application/json", forHTTPHeaderField: "Accept");

var httpBodyDictionary: NSMutableDictionary = NSMutableDictionary();
httpBodyDictionary.setObject(self.emailTextField.text, forKey: "email");
httpBodyDictionary.setObject(self.usernameTextField.text, forKey: "username");
httpBodyDictionary.setObject(self.passwordTextField.text, forKey: "password");

urlRequest.HTTPMethod = "POST";

NSURLConnection.sendAsynchronousRequest(urlRequest, queue: NSOperationQueue.mainQueue(), completionHandler: { (response: NSURLResponse!, data: NSData!, error: NSError!) -> Void in
    if(data != nil) {
          //PROCESS DATA
    }
});

我尝试过 Alamofire，但我无法让它工作..

阿拉莫火

var defaultHeaders = Alamofire.Manager.sharedInstance.session.configuration.HTTPAdditionalHeaders ?? [:]
defaultHeaders["Authorization"] = "\(base64LoginString))"
defaultHeaders["Content-Type"] = "application/json)"
defaultHeaders["Accept"] = "application/json)"

let configuration = NSURLSessionConfiguration.defaultSessionConfiguration()
configuration.HTTPAdditionalHeaders = defaultHeaders;

let manager = Alamofire.Manager(configuration: configuration)


var requestString: NSString = "http://api.domainname.com/api/v1/auth/register";
var url: NSURL = NSURL(string: requestString.stringByAddingPercentEscapesUsingEncoding(NSUTF8StringEncoding)!)!;

var urlRequest: NSMutableURLRequest = NSMutableURLRequest(URL: url);
urlRequest.HTTPMethod = Alamofire.Method.POST.rawValue;

let parameters = ["email": self.emailTextField.text,
        "username": self.usernameTextField.text,
        "password": self.passwordTextField.text]

do {
        urlRequest.HTTPBody = try NSJSONSerialization.dataWithJSONObject(parameters, options: NSJSONWritingOptions())
} catch {
    // No-op
}

Alamofire.request(urlRequest).responseJSON(completionHandler: { (urlRequest, urlResponse, result) -> Void in
        print(urlResponse);        
    //print(result);
})

请有人指出正确的方向吗？我花了一整天的时间试图让它发挥作用。

注意：使用 Swift 2/XCode 7 Beta 6

UPDATE 尝试了 Rob 的建议，但我得到了返回，当我使用 NSURLConnection 时不会发生这种情况

打印的回复

Optional(<NSHTTPURLResponse: 0x7fdbc222a2b0> { URL: http://api.domainname.com/api/v1/auth/register } { status code: 422, headers {
    "Cache-Control" = "no-cache, proxy-revalidate";
    Connection = "Keep-Alive";
    "Content-Type" = "application/json";
    Date = "Thu, 10 Sep 2015 14:35:13 GMT";
    Server = "nginx/1.8.0";
    "Set-Cookie" = "laravel_session=eyJpdiI6InZjSVwvcVd3NjR6SitZSlZNMGdXdElRPT0iLCJ2YWx1ZSI6IjJBeXdWTHRlRUNQa2RTSFBDYlU0bWlBRkF3c0pzcEx2YzQxdXk0ZnlxZ2xERUkrWmFZNlNISUlyZmpnWjZkamdxVFJXaGxOQmFtVlZZWElWdnFYdlBRPT0iLCJtYWMiOiI5MWY2NjU4ODViYjhlYWM4N2YwOTg2ZTA2OWYzNmU1MmE3ZWEzN2E5ZTA5ZjA5YjMyYmExN2FmMzFhZjRiMmJhIn0%3D; expires=Thu, 10-Sep-2015 16:35:13 GMT; Max-Age=7200; path=/; httponly";
    "Transfer-Encoding" = Identity;
} })

Answer 1

您不必设置Content-Type 或Accept。您也不必自己设置请求正文或使用NSJSONSerialization。 Alamofire 让您摆脱构建请求的麻烦。所以你可能会这样做：

let requestString = "http://api.domainname.com/api/v1/auth/register"

let parameters = [
    "email"    : emailTextField.text!,
    "username" : usernameTextField.text!,
    "password" : passwordTextField.text!
]

let headers = ["Authorization": base64LoginString]

Alamofire.request(.POST, requestString, parameters: parameters, encoding: .JSON, headers: headers).responseJSON { request, response, result in
    print(response)
}

或者，如果您不想自己构建base64LoginString，您也可以执行以下操作：

Alamofire.request(.POST, requestString, parameters: parameters, encoding: .JSON)
    .authenticate(user: user, password: password)
    .responseJSON { request, response, result in
        print(response)
}

如果仍然无法正常工作，我建议 (a) 编辑您的问题，分享准确的错误消息； (b) 在Charles 之类的工具中观察您的旧代码和新代码，并确定这两个请求的差异程度。