POST 请求成功后打开第二个控制器

Question

我只学习 Obj-c。我正在发送登录名和密码，返回 html 页面，如何在请求后打开页面并关闭 loginWindowController？是请求本身：

    NSString *myLogin = usernameTextField.stringValue;
    NSString *myPassword = passwordTextField.stringValue;
    NSString *myFlash = flashpasswordTextField.stringValue;
    NSString *myNid = @"123456";
    NSString *urlString = @"http://neverlands.ru/game.php";
    NSString *ua = @"Mozilla/5.0 (Macintosh; Intel Mac OS X 10_10_2) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/41.0.2272.89 Safari/537.36";

    AFHTTPRequestOperationManager *manager = [AFHTTPRequestOperationManager manager];
    manager.responseSerializer = [AFHTTPResponseSerializer serializer];
    AFHTTPRequestSerializer * requestSerializer = [AFHTTPRequestSerializer serializer];
    [requestSerializer setValue:ua forHTTPHeaderField:@"User-Agent"];
    manager.requestSerializer = requestSerializer;
    AFHTTPResponseSerializer * responseSerializer = [AFHTTPResponseSerializer serializer];
    manager.responseSerializer = responseSerializer;
    NSDictionary *parameters = @{@"player_nick": myLogin, @"player_password": myPassword};
    [manager POST:urlString parameters:parameters success:^(AFHTTPRequestOperation *operation, id responseObject) {
        //Условия после запроса 1
        if ([operation.responseString rangeOfString:@"NeverLands: Земли, которых нет... - Второй пароль"].location == NSNotFound) {
            NSLog(@"Неверный логин или пароль");
        } else {
            NSDictionary *parameters = @{@"flcheck": myFlash, @"nid": myNid};
            [manager POST:urlString parameters:parameters success:^(AFHTTPRequestOperation *operation, id responseObject) {
                //Условия после запроса 2
                if ([operation.responseString rangeOfString:@"NeverLands: Земли, которых нет... - бесплатная браузерная онлайн игра в стиле фэнтези"].location == NSNotFound) {
                    NSLog(@"Неверный флеш пароль");
                } else {
                    mainWindowController = [[MainWindowController alloc] initWithWindowNibName:@"MainWindow"];
                    [mainWindowController showWindow:self];
                    [mainWindowController addWebView:[NSURL URLWithString:urlString]];
                    NSLog(@"Авторизация произведена");
                }
            } failure:^(AFHTTPRequestOperation *operation, NSError *error) {
                NSLog(@"Error: %@", error);
            }];
        }
    } failure:^(AFHTTPRequestOperation *operation, NSError *error) {
        NSLog(@"Error: %@", error);
    }];

在这里写什么会打开当前会话？

  mainWindowController = [[MainWindowController alloc] initWithWindowNibName:@"MainWindow"];
                [mainWindowController showWindow:self];
                [mainWindowController addWebView:[NSURL URLWithString:HERE]];

我试过[mainWindowController addWebView:[NSURL URLWithString:urlString]];但是打开一个新会话的页面并写道没有输入用户名和密码。

Answer 1

看起来您正在发出相同的发布请求，具有相同的正文，但在响应中寻找 2 个不同的内容？

您应该对响应正文进行 2 次检查

NSString *importantStuff1 = @"NeverLands: Земли, которых нет... - Второй пароль";
NSString *importantStuff2 = @"NeverLands: Земли, которых нет... - бесплатная браузерная онлайн игра в стиле фэнтези";
if (([operation.responseString rangeOfString:importantStuff1].location == NSNotFound) &&
([operation.responseString rangeOfString:importantStuff2].location == NSNotFound))
{
  NSLog(@"Couldn't find the important stuff needed");
}
else
{
    mainWindowController = [[MainWindowController alloc] initWithWindowNibName:@"MainWindow"];
    [mainWindowController showWindow:self];
    [mainWindowController addWebView:[NSURL URLWithString:urlString]];
    NSLog(@"Авторизация произведена");
}

请原谅变量名我不知道这些词是什么哈哈