【问题标题】:Push notification Chrome Mobile Ver 42+推送通知 Chrome Mobile Ver 42+
【发布时间】:2015-08-06 10:42:18
【问题描述】:

我正在尝试本文建议的推送通知演示。 https://developers.google.com/web/updates/2015/03/push-notificatons-on-the-open-web?hl=en

并尝试从 github https://github.com/GoogleChrome/samples/tree/gh-pages/push-messaging-and-notifications 运行代码

按照指示,我做了以下事情 -
1. 在谷歌开发者控制台上创建项目。
2. config.js 中添加浏览器应用密钥 > gcmAPIKey :'browser api key'
3.在 manifest.json 中添加 gsm_sender_id :'Project number'
4. 在https://somedomain.com上托管应用程序
结果是


每当我单击 SendPushMessage 按钮时,它都不会显示任何通知。在调试时,我发现这个请求被触发了
https://xxsomedomainxxx.azurewebsites.net/api/get/?subscriptionId=APA91bE_xyl2sP8l1pa8j4n84VGfJgKVb28I0DJK5qo9zUVLy0ZSRsyl2BbjLDSZ-Y625LqsmMp3rIH4PW3s1v_ccBOdCbWYsxaF525FHRbx5odr-z1a1uPrP4zqy4DFlKkwa9pyHhkdxL0ggxGBbC_bB6LTZSDuTKlDeXTRhywcY9X5KxBXrxhS_4M8oJFUi3eW6FikEUiJ

根据我的观察,我需要在服务器上捕获 substriptionId 并需要对其进行处理。那么我需要在服务器上为以下 API 编写什么样的代码

https://xxsomedomainxxx.azurewebsites.net/api/get/

【问题讨论】:

    标签: c# .net google-chrome push-notification chrome-gcm


    【解决方案1】:

    我使用以下代码创建了一个 WCF REST 服务,并将通知发送到 android chrome 42+。
    但是这里有一个问题,通知显示来自 service-worker.js 文件的消息,而不是来自此代码

    var value = "来自服务器的问候";

    。我正在努力,很快就会更新这个答案。

    请在 main.js 文件中更新此函数


    function getNotification(subscription) {
    
        navigator.serviceWorker.ready.then(function (serviceWorkerRegistration) {
            serviceWorkerRegistration.pushManager.subscribe()
              .then(function (subscription) {
                  console.log('getNotification', subscription)
                  fetch('/pushnotificationservice.svc/sendnotification?key=' + subscription.subscriptionId).then(function (obj) {
                      console.log('getNotification', obj)
                  });
              });
        });
    

    WCF 服务代码

    public string SendNotification(string key)
            {
                 ServiceData myServiceData = new ServiceData();
                try
                {
                    string GoogleAppID = "2440XXXXXXXX";//put your project number here
                    string redId = key;
                    var SENDER_ID = "youremail@gmail.com";//I haven't tried with another junk value
                    var value = "Hello from server";//this message do not displayed in notification
                    WebRequest tRequest;
                    tRequest = WebRequest.Create("https://android.googleapis.com/gcm/send");
                    tRequest.Method = "post";
                    tRequest.ContentType = " application/x-www-form-urlencoded;charset=UTF-8";
    
                    tRequest.Headers.Add(string.Format("Authorization: key={0}", "Your browser key"));
    
                    tRequest.Headers.Add(string.Format("Sender: id={0}", SENDER_ID));
    
                    string postData = "collapse_key=score_update&time_to_live=108&delay_while_idle=1&data.message=" + value + "&data.time=" + System.DateTime.Now.ToString() + "&registration_id=" + key + "";
                    Console.WriteLine(postData);
                    Byte[] byteArray = Encoding.UTF8.GetBytes(postData);
                    tRequest.ContentLength = byteArray.Length;
    
                    Stream dataStream = tRequest.GetRequestStream();
                    dataStream.Write(byteArray, 0, byteArray.Length);
                    dataStream.Close();
    
                    WebResponse tResponse = tRequest.GetResponse();
    
                    dataStream = tResponse.GetResponseStream();
    
                    StreamReader tReader = new StreamReader(dataStream);
    
                    String sResponseFromServer = tReader.ReadToEnd();
    
                    tReader.Close();
                    dataStream.Close();
                    tResponse.Close();
                    return sResponseFromServer;
                }
                catch (FaultException fex)
                {
                    myServiceData.Result = false;
                    myServiceData.ErrorMessage = "unforeseen error occurred. Please try later.";
                    myServiceData.ErrorDetails = fex.ToString();
                    throw new FaultException<ServiceData>(myServiceData);
                }
            }
    

    【讨论】:

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