在Objective C（iOS）中向远程推送通知添加消息

Question

如何从动态通知服务中获取并显示推送通知中的消息

push: {
    aps =  {
        alert = "My First Notification";
        sound = default;
        Msg = {
            myData = (
                      {
                        Msg = "Awesome";
                        Id = 123;
                        Date = "Jan 18 2018";
                       }
                      );
              };
           };
       }

因为我想在推送通知到达时显示 alert = "My First Notification" 和 Msg = "Awesome"。我不知道如何获取和显示。请帮我解决这个问题。 TIA

我试过下面的代码

- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions {
    // Override point for customization after application launch.

    [application registerUserNotificationSettings:[UIUserNotificationSettings settingsForTypes:(UIUserNotificationTypeSound | UIUserNotificationTypeAlert | UIUserNotificationTypeBadge) categories:nil]];

    [application registerForRemoteNotifications];


    return YES;
}

- (void)application:(UIApplication*)application didRegisterForRemoteNotificationsWithDeviceToken:(NSData*)deviceToken
{
    NSLog(@"My token is: %@", deviceToken);

    NSString *deviceTokenStr = [[[[deviceToken description]
                                  stringByReplacingOccurrencesOfString: @"<" withString: @""]
                                 stringByReplacingOccurrencesOfString: @">" withString: @""]
                                stringByReplacingOccurrencesOfString: @" " withString: @""];

    NSLog(@"Device Token: %@", deviceTokenStr);
}

- (void)application:(UIApplication*)application didFailToRegisterForRemoteNotificationsWithError:(NSError*)error
{
    NSLog(@"Failed to get token, error: %@", error);
}

- (void)application:(UIApplication*)application didReceiveRemoteNotification:(NSDictionary*)userInfo
{
    NSLog(@"Received notification: %@", userInfo);
    NSUserDefaults * loginDefaults = [NSUserDefaults standardUserDefaults];

    UIApplicationState state = [[UIApplication sharedApplication] applicationState];
    if (UIApplicationStateActive == state )
    {

        return;
    }

}

我只想在推送通知中显示它。

Answer 1

据我了解，您希望您的推送在通知屏幕上显示标题My First Notification 和消息（或正文）Awesome。为此，您无需在应用程序中编写代码。真正发挥作用的是有效载荷的结构。

目前您正在以

的形式发送有效负载

{
  "aps": {
    "alert": "My First Notification",
    "sound": "default",
    "Msg": {
      "myData": [
        {
          "Msg": "Awesome",
          "Id": 123,
          "Date": "Jan 18 2018"
        }
      ]
    }
  }
}

根据apple docs，通知屏幕上不会显示Awesome消息

要在通知屏幕上显示Awesome 消息，您需要指定body 键。创建如下所示的有效负载并发送此推送，您将在通知屏幕上看到标题和正文。还可以通过上述文档了解更多信息

{
  "aps": {
    "alert": {
      "title": "My First Notification",
      "body": "Awesome",
      "sound": "default"
    }
  },
  "myData": {
    "Id": 123,
    "Date": "Jan 18 2018"
  }
}

最后我想补充一点，在 android 中我们需要在应用程序中编写代码来显示推送通知，而在 ios 中我们不必编写代码或更准确地说我们的应用程序不需要控制推送的显示方式。这完全取决于使用适当密钥向 APNS 发送数据的服务器

Answer 2

首先UserInfo 是NSDictionary，所以你可以通过键获取所有需要的值，你的情况是这样的

代码

NSDictionary * aps = [userInfo objectForKey:@"aps"];
NSDictionary * myData = [aps objectForKey:@"Msg"];
//inside of Msg dictionary you have an array of dictionaries
NSArray * arrayOfData = [myData objectForKey:@"myData"];
NSLog(@"%@",[arrayOfData objectAtIndex:0]);
NSDictionary * infoDict = [arrayOfData objectAtIndex:0];
//here we get the message!!!
NSString* message = [infoDict objectForKey:@"Msg"];
//then show your alert
UIAlertController* alertController = [UIAlertController alertControllerWithTitle:NSLocalizedString(@"My First Notification", nil) message:message preferredStyle:UIAlertControllerStyleAlert];
[[[self window] rootViewController] presentViewController:alertController animated:true completion:nil];

此代码未经测试，如果有问题，请告诉我，但这就是想法