【发布时间】:2017-11-06 12:34:20
【问题描述】:
我正在使用用于 Android 23 API 的 quickblox。我想在呼叫建立之前将用户信息从一个呼叫者传递到另一个呼叫者。 为此,我使用了 QBRTCSession 的“用户信息”部分并放入了一个键值对。但对于另一端,它为“userinfo”提供空值。有人可以提出可能的原因并提出解决方案吗?
两个调用的会话 ID 相同。开始调用函数-
private void startCall(boolean isVideoCall) {
if (opponentsAdapter.getSelectedItems().size() > Consts.MAX_OPPONENTS_COUNT) {
Toaster.longToast(String.format(getString(R.string.error_max_opponents_count),
Consts.MAX_OPPONENTS_COUNT));
return;
}
Log.d(TAG
, "startCall()");
//ArrayList<Integer> opponentsList = CollectionsUtils.getIdsSelectedOpponents(opponentsAdapter.getSelectedItems());
ArrayList<Integer> opponentsList = new ArrayList<>();
opponentsList.add(currentOpponentsList.get(0).getId());
QBRTCTypes.QBConferenceType conferenceType = isVideoCall
? QBRTCTypes.QBConferenceType.QB_CONFERENCE_TYPE_VIDEO
: QBRTCTypes.QBConferenceType.QB_CONFERENCE_TYPE_AUDIO;
QBRTCClient qbrtcClient = QBRTCClient.getInstance(getApplicationContext());
QBRTCSession newQbRtcSession = qbrtcClient.createNewSessionWithOpponents(opponentsList, conferenceType);
newQbRtcSession.getUserInfo().put("som","name");
Log.v("SessionThing",newQbRtcSession.getSessionDescription().toString());
WebRtcSessionManager.getInstance(this).setCurrentSession(newQbRtcSession);
// newQbRtcSession.
PushNotificationSender.sendPushMessage(opponentsList, "Hello"+currentUser.getFullName());
Toast.makeText(getApplicationContext(),name,Toast.LENGTH_LONG).show();
CallActivity.start(this, false);
Log.d(TAG, "conferenceType = " + conferenceType);
}
通话中-
public void onReceiveNewSession(final QBRTCSession session) {
Log.d("userinfo_needed", "Session " + session.getSessionID() + " are income");
Log.v("qbrtcsession",session.getSessionDescription().toString());
userInfo = session.getUserInfo();
if (getCurrentSession() != null) {
//userInfo = session.getUserInfo();
Log.d(TAG, "Stop new session. Device now is busy");
session.rejectCall(null);
}
}
In IncomeCallFragment - toast 给出 null
private void initUI(View view) {
callTypeTextView = (TextView) view.findViewById(R.id.call_type);
ImageView callerAvatarImageView = (ImageView) view.findViewById(R.id.image_caller_avatar);
callerAvatarImageView.setBackgroundDrawable(getBackgroundForCallerAvatar(currentSession.getCallerID()));
TextView callerNameTextView = (TextView) view.findViewById(R.id.text_caller_name);
QBUser callerUser = qbUserDbManager.getUserById(currentSession.getCallerID());
callerNameTextView.setText(UsersUtils.getUserNameOrId(callerUser, currentSession.getCallerID()));
Toast.makeText(getActivity().getApplicationContext(),currentSession.getSessionDescription().getUserInfo()+" ", Toast.LENGTH_LONG).show();
TextView otherIncUsersTextView = (TextView) view.findViewById(R.id.text_other_inc_users);
otherIncUsersTextView.setText(getOtherIncUsersNames());
alsoOnCallText = (TextView) view.findViewById(R.id.text_also_on_call);
setVisibilityAlsoOnCallTextView();
rejectButton = (ImageButton) view.findViewById(R.id.image_button_reject_call);
takeButton = (ImageButton) view.findViewById(R.id.image_button_accept_call);
accept();
}
【问题讨论】:
-
你在哪里调用 session.startcall() .??
-
你得到答案了吗?
-
@user2828360 你有什么解决办法吗?请回复
标签: android session webrtc quickblox