【问题标题】:Connect to Google Talk using smack使用 smack 连接到 Google Talk
【发布时间】:2012-08-01 09:32:46
【问题描述】:

我想开发一个连接到 Google Talk 并允许用户与其朋友聊天的 Java 应用程序。我正在使用 smack API 和下面的代码:

ConnectionConfiguration config = new ConnectionConfiguration("talk.google.com",5222,"gmail.com");
SASLAuthentication.supportSASLMechanism("PLAIN", 0);
XMPPConnection connection  = new XMPPConnection(config);
try {
    connection.connect();
} catch (XMPPException e) {
    e.printStackTrace();
}
try {
    connection.login("username", "password");
} catch (XMPPException e) {
    e.printStackTrace();
}

但我得到了休闲异常:

SASL authentication PLAIN failed: invalid-authzid: 
    at org.jivesoftware.smack.SASLAuthentication.authenticate(SASLAuthentication.java:337)
    at org.jivesoftware.smack.XMPPConnection.login(XMPPConnection.java:203)
    at org.jivesoftware.smack.Connection.login(Connection.java:348)
    at Main.main(Main.java:21)

谁能帮我解决这个问题?

【问题讨论】:

    标签: java smack google-talk


    【解决方案1】:

    这应该可以解决问题,非常简单

    import org.jivesoftware.smack.Chat;
    import org.jivesoftware.smack.ChatManager;
    import org.jivesoftware.smack.ConnectionConfiguration;
    import org.jivesoftware.smack.MessageListener;
    import org.jivesoftware.smack.XMPPConnection;
    import org.jivesoftware.smack.XMPPException;
    import org.jivesoftware.smack.packet.Message;
    import org.jivesoftware.smack.packet.Presence;
    
     public class SenderTest 
    {
    public static void main(String args[])
    {
        //ConnectionConfiguration connConfig = new ConnectionConfiguration("localhost", 5222);
            //connConfig.setSASLAuthenticationEnabled(false);
         //ConnectionConfiguration connConfig = new ConnectionConfiguration("localhost", 5222);
         ConnectionConfiguration connConfig = new ConnectionConfiguration("talk.google.com", 5222, "gmail.com");
           XMPPConnection connection = new XMPPConnection(connConfig);
    
            try {
                connection.connect();
                System.out.println("Connected to " + connection.getHost());
            } catch (XMPPException ex) {
                //ex.printStackTrace();
                System.out.println("Failed to connect to " + connection.getHost());
                System.exit(1);
            }
            try {
                connection.login("sender@example.com", "a");
                System.out.println("Logged in as " + connection.getUser());
    
                Presence presence = new Presence(Presence.Type.available);
                connection.sendPacket(presence);
    
            } catch (XMPPException ex) {
                //ex.printStackTrace();
                System.out.println("Failed to log in as " + connection.getUser());
                System.exit(1);
            }
    
        ChatManager chatmanager = connection.getChatManager();
        Chat newChat = chatmanager.createChat("receiver@gmail.com", new MessageListener() {
            public void processMessage(Chat chat, Message message) {
                System.out.println("Received message: " + message);
            }
        });
    
        try {
            newChat.sendMessage("Howdy!");
            System.out.println("Message Sent...");
        }
        catch (XMPPException e) {
            System.out.println("Error Delivering block");
        }
    }
    
    }
    

    【讨论】:

      【解决方案2】:

      这是我使用 smack 连接到 google talk 的方法。

       private ConnectionStatus status;
       private XMPPConnection xmppConnection;
      
      public void connect(String server, int port, String s) throws Exception
      {
      xmppConnection = new XMPPConnection(new ConnectionConfiguration(server, port,s));
      xmppConnection.connect();
      xmppConnection.addConnectionListener(this);
      xmppConnection.getChatManager().addChatListener(this); 
      }
      

      和身份验证。

      public void authenticate(String username, String password) throws Exception
      {
        xmppConnection.login(username, password);
      buddyList.setSession(xmppConnection);
      setStatus(ConnectionStatus.AUTHENITCATED);
      }
      

      【讨论】:

      • 谢谢,我成功登录了,但由于某种原因,我得到了一个异常,我不知道如何发布它
      • 可以登录但出现异常?能发第一行吗?
      【解决方案3】:

      这拯救了我的一天

      connectionConfig = new ConnectionConfiguration(host, port, service);
      connectionConfig.setSASLAuthenticationEnabled(false);
      connectionConfig.setTruststoreType("BKS");
      connection = new XMPPConnection(connectionConfig);
      

      【讨论】:

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