将 NSArray 写入 plist 文件

Question

我有一个获取 plist 文件数据的代码和一个将数据写入 plist 文件的代码。现在的事情是，它将读取的数据添加到一个数组中（参见图片）。 我想要它在不同的数组中（见绿色图像）

这是我的代码：

- (void)WriteData {
NSFileManager *fileManager = [NSFileManager defaultManager];
NSError *error;
NSArray *paths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES);
NSString *documentsDirectory = [paths objectAtIndex:0];

NSString *path = [documentsDirectory stringByAppendingPathComponent:@"MuziekList.plist"];

if ([fileManager fileExistsAtPath:path] == NO) {
    NSString *resourcePath = [[NSBundle mainBundle] pathForResource:@"MuziekList" ofType:@"plist"];
    [fileManager copyItemAtPath:resourcePath toPath:path error:&error];
}
//_______________________________________________________________________________________________________________
NSMutableDictionary *savedStock = [[NSMutableDictionary alloc] initWithContentsOfFile: path];

//load from savedStock example int value
NSArray *NummerTexts;
NummerTexts = [savedStock objectForKey:@"Nummers"];
NSString *NummerTextsR = [[NummerTexts valueForKey:@"description"] componentsJoinedByString:@" - "];

NSArray *ArtiestTexts;
ArtiestTexts = [savedStock objectForKey:@"Artiesten"];
NSString *ArtiestTextsR = [[ArtiestTexts valueForKey:@"description"] componentsJoinedByString:@" - "];
//_______________________________________________________________________________________________________________

NSUserDefaults *CurrentVideoNummerResult = [NSUserDefaults standardUserDefaults];
NSString *CurrentVideoNummer = [CurrentVideoNummerResult stringForKey:@"CurrentVideoNummer"];

NSUserDefaults *CurrentVideoArtiestResult = [NSUserDefaults standardUserDefaults];
NSString *CurrentVideoArtiest = [CurrentVideoArtiestResult stringForKey:@"CurrentVideoArtiest"];

/*
NSUserDefaults *CurrentVideoIDResult = [NSUserDefaults standardUserDefaults];
NSString *CurrentVideoID = [CurrentVideoIDResult stringForKey:@"CurrentVideoID"];
*/

NSMutableDictionary *plist = [[NSDictionary dictionaryWithContentsOfFile:path] mutableCopy];
NSMutableArray *newArray = [[NSMutableArray alloc] init];
NSMutableArray *newArray2 = [[NSMutableArray alloc] init];

newArray = [NSMutableArray arrayWithObjects:CurrentVideoNummer, NummerTextsR, nil];
[plist setObject:newArray forKey:@"Nummers"];


newArray2 = [NSMutableArray arrayWithObjects:CurrentVideoArtiest, ArtiestTextsR, nil];
[plist setObject:newArray2 forKey:@"Artiesten"];

[plist writeToFile:path atomically:YES];
}

点击图片链接

https://www.dropbox.com/sh/wrk8h8cnwye8myx/AADl4omkGdl3S4ESXv6NbymVa?dl=0

Answer 1

您的问题和问题令人困惑。也许这会有所帮助：

您的代码读取当前数组 (NummerTexts)，将该数组展平为单个字符串 (NummerTextsR)，获取第二个字符串 (CurrentVideoNummer)，然后构建一个双元素数组 (newArray) .

你的问题似乎是为什么你会得到一个二元素数组...？

如果您不想展平原始数组，请不要这样做，只需制作它的可变副本，例如：

NSMutableArray *existingTexts = [[NummerTexts valueForKey:@"description"] mutableCopy];

添加你的新元素：

[existingTexts addObject:currentVideoNummer];

然后像以前一样写回去。

HTH

顺便说一句，不要以大写字母开头局部变量名，这违反了约定，这就是为什么你的问题中突出显示的语法都是错误的。