如何使用 curl 下载 IP2Location 数据库答案

【问题标题】：How to download IP2Location database with curl如何使用 curl 下载 IP2Location 数据库
【发布时间】：2020-10-14 19:04:54
【问题描述】：

我正在尝试使用他们提供的 curl 命令从 IP2Location 下载数据库。我已注册，所以我有一个有效的令牌。他们给出的命令是

    curl -o {LOCAL_FILE_NAME} "https://www.ip2location.com/download?token={DOWNLOAD_TOKEN}&file={DATABASE_CODE}"

这是我正在使用的代码，除了我的令牌：

    $curl = curl_init();
    curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);
    curl_setopt($curl, CURLOPT_URL, "https://www.ip2location.com/download?token={mytoken}&file={DB1LITEBIN}");

    $dbfile = curl_exec($curl);

    if (curl_errno($curl)) {
     echo 'err '.curl_errno($curl);
    }                  

    curl_close($curl);

    $file = 'db_download.bin';  
    $mode = 'w';

     if (($fp = fopen($file , $mode))) {    
       $fout = fwrite($fp, $dbfile);
       fclose($fp);  
    }

脚本运行没有错误，但下载的文件只是他们网站的未找到页面。如果我在浏览器中使用 url，我会找不到相同的页面。有人可以指出我的错误吗？

【问题讨论】：

标签： curl download ip2location

【解决方案1】：

请尝试以下操作。请注意，您将下载一个包含 bin 文件的 zip 文件。

<?php

//The resource that we want to download.
$fileUrl = 'https://www.ip2location.com/download?token=XXXXXXXXXX&file=DB1LITEBIN';

//The path & filename to save to.
$saveTo = 'db_download.zip';

//Open file handler.
$fp = fopen($saveTo, 'w+');

//If $fp is FALSE, something went wrong.
if($fp === false){
    throw new Exception('Could not open: ' . $saveTo);
}

//Create a cURL handle.
$ch = curl_init($fileUrl);

//Pass our file handle to cURL.
curl_setopt($ch, CURLOPT_FILE, $fp);

//Timeout if the file doesn't download after 20 seconds.
curl_setopt($ch, CURLOPT_TIMEOUT, 20);

curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 0);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, 0);

//Execute the request.
curl_exec($ch);

//If there was an error, throw an Exception
if(curl_errno($ch)){
    throw new Exception(curl_error($ch));
}

//Get the HTTP status code.
$statusCode = curl_getinfo($ch, CURLINFO_HTTP_CODE);

//Close the cURL handler.
curl_close($ch);

//Close the file handler.
fclose($fp);

if($statusCode == 200){
    echo 'Downloaded!';
} else{
    echo "Status Code: " . $statusCode;
}

【讨论】：