【发布时间】:2017-01-19 02:58:28
【问题描述】:
我在尝试连接到运行同一应用的多台设备时遇到问题。我的应用程序的工作流程是:
- 一个设备调用发现对等点(参见代码 A)
- 一旦发现对等点,我会显示一个 AlertDialog,允许用户选择他们想要连接的对等点(参见代码 B)
- 一旦用户选择了他们想要连接的设备,我会尝试遍历 WifiP2pDeviceList 并在每个传入的设备上调用 connect 方法(我总是将当前设备的意图设置为组所有者)(请参阅代码 C)
- 一旦建立连接,我会传输一些数据....
问题:在第3步中,当我调用connect方法时,代码连接到第一个设备没有任何问题,但是当它到达第二个循环迭代时连接到第二个或第三个选择的设备 我遇到故障,原因代码为 2(忙)。为什么会这样?当我只连接一个设备时,一切正常,只有当我尝试连接多个设备时才会出现问题?我究竟做错了什么?我找不到任何有关如何连接到多个设备的示例...非常感谢任何帮助。
代码 A:(发现同行)
private WifiP2pManager mManager;
mManager.discoverPeers(mChannel, new WifiP2pManager.ActionListener() {
@Override
public void onSuccess() {
onInitiateDiscovery();
}
@Override
public void onFailure(int reasonCode) {
Toast.makeText(getActivity(), "Discovery Failed: " + getReascodeText(reasonCode), Toast.LENGTH_SHORT).show();
}
});
代码 B:(选择要连接的对等方)
public void onPeersAvailable(WifiP2pDeviceList peers) {
final ArrayList<Integer> itemsSelected = new ArrayList<>();
// Out with the old, in with the new.
mPeers.clear();
mPeers.addAll(peers.getDeviceList());
CharSequence[] cs = StringUtils.getDeviceNames(mPeers);
AlertDialog.Builder builder = new AlertDialog.Builder(getActivity());
builder.setTitle("Who do you want to share with?");
builder.setMultiChoiceItems(cs, null, new DialogInterface.OnMultiChoiceClickListener() {
public void onClick(DialogInterface dialog, int selectedItemId, boolean isChecked) {
if (isChecked) {
itemsSelected.add(selectedItemId);
} else if (itemsSelected.contains(selectedItemId)) {
itemsSelected.remove(Integer.valueOf(selectedItemId));
}
}
}).setPositiveButton("Done!", new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialog, int id) {
WifiP2pDevice wifiP2pDevice = mPeers.get(itemsSelected.get(0));
List<WifiP2pDevice> devices = extractSelectedDevices(itemsSelected,mPeers);
numConnections = devices.size();
connect(devices);
}
});
mPeerSelectionDialog = builder.create();
mPeerSelectionDialog.show();
}
代码 C:(连接到选定的设备)
public void connect(List<WifiP2pDevice> devices) {
for(WifiP2pDevice device: devices) {
WifiP2pConfig config = new WifiP2pConfig();
config.deviceAddress = device.deviceAddress;
config.wps.setup = WpsInfo.PBC;
config.groupOwnerIntent = 15;
mManager.connect(mChannel, config, new WifiP2pManager.ActionListener() {
@Override
public void onSuccess() {
// WiFiDirectBroadcastReceiver will notify us. Ignore for now.
System.out.println("successfully connected!!");
Log.d(MultiImageSelectorFragment.TAG, ">>>>>>>>>>>>>>>>>>>>>!!Successfully Connected!<<<<<<<<<<<");
}
@Override
public void onFailure(int reason) {
Toast.makeText(getActivity(), "Connect failed. Retry.", Toast.LENGTH_SHORT).show();
Log.d(MultiImageSelectorFragment.TAG, ">>>>>>>>>>>>>>>>>>>>>!!Failed connection, rasoncode:"+reason+" !<<<<<<<<<<<");
}
});
}
【问题讨论】:
-
我遇到了同样的问题。您能否分享一下您解决问题的代码。提前谢谢你。
标签: android wifi-direct wifimanager wifip2p