【发布时间】:2018-07-18 14:20:35
【问题描述】:
我有以下 SQL 查询:
SELECT
vac.vacancy_id AS vacancy_id,
vac.title AS vacancy_title,
vac.slug AS vacancy_slug,
vac.company_name AS vacancy_company_name,
vac.company_latitude AS vacancy_company_latitude,
vac.company_longitude AS vacancy_company_longitude,
cat.slug AS vacancy_category_slug,
(
6371 *
acos(
cos( radians( :latitude ) ) *
cos( radians( vac.company_latitude ) ) *
cos(
radians( vac.company_longitude ) - radians( :longitude )
) +
sin( radians( :latitude ) ) *
sin( radians( vac.company_latitude ) )
)
) AS distance
FROM
vacancies vac
JOIN
vacancies_categories cat
ON
vac.vacancy_category_id = cat.vacancy_category_id
WHERE
vac.subdomain = :subdomain
AND
distance < :distance
AND
vac.company_latitude IS NOT NULL
AND
vac.company_longitude IS NOT NULL
这会获取地址周围圆形距离内的所有空缺。
当我删除以下行时,它工作:
AND
distance < :distance
但是当我添加这段代码时,它不起作用。但我想设置一个最大值。距离。
PHP:
$stmtSelectVacancies = $db->prepare($querySelectVacancies);
$stmtSelectVacancies->bindParam(':latitude', $latitude);
$stmtSelectVacancies->bindParam(':longitude', $longitude);
$stmtSelectVacancies->bindParam(':subdomain', $subdomain);
$stmtSelectVacancies->bindParam(':distance', $distance);
$stmtSelectVacancies->execute();
// and so on...
我还在 WHERE 子句之前尝试了 HAVING 子句(HAVING 距离
谁有想法?
提前致谢!
【问题讨论】:
标签: php mysql geolocation