如何在 BroadcastReceiver 服务中获取经纬度值？

Question

所以我制作了一个应用程序，如果按下手机的电源按钮 5 次，该应用程序就会运行，该应用程序将在后台执行类似于打开 url 的操作。现在的问题是我想在那个时候提取纬度和经度值。 代码是

LockService 类

public class LockService extends Service {

    @Override
    public IBinder onBind(Intent intent) {
        return null;
    }

    @Override
    public void onCreate() {
        super.onCreate();
    }

    @Override
    public int onStartCommand(Intent intent, int flags, int startId) {
        final IntentFilter filter = new IntentFilter(Intent.ACTION_SCREEN_ON);
        filter.addAction(Intent.ACTION_SCREEN_OFF);
        filter.addAction(Intent.ACTION_USER_PRESENT);
        final BroadcastReceiver mReceiver = new ScreenReceiver();
        registerReceiver(mReceiver, filter);
        return super.onStartCommand(intent, flags, startId);
    }
    public class LocalBinder extends Binder {
        LockService getService() {
            return LockService.this;
        }
    }
}

屏幕接收器

public class ScreenReceiver extends BroadcastReceiver {

    LocationManager locationManager;
    static int countPoweroff =0;

    public static boolean wasScreenOn = true;
    int lol;
    @Override
    public void onReceive(final Context context, final Intent intent) {

        Log.e("LOB","onReceive");
        if (intent.getAction().equals(Intent.ACTION_SCREEN_OFF)) {
            // do whatever you need to do here

            wasScreenOn = false;
            countPoweroff++;
            Log.e("LOB",""+countPoweroff);
            Log.e("LOB","wasScreenOn"+wasScreenOn);
        } else if (intent.getAction().equals(Intent.ACTION_SCREEN_ON)) {
            // and do whatever you need to do here
            if (countPoweroff == 3){
                Log.e("LOB","userpresent");
                Log.e("LOB","wasScreenOn"+wasScreenOn);
                String url = "http://www.stackoverflow.com";
                Intent i = new Intent(Intent.ACTION_VIEW);
                i.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
                i.setData(Uri.parse(url));
                context.startActivity(i);

                Vibrator vibrator = (Vibrator) context.getSystemService(Context.VIBRATOR_SERVICE);
                if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) {
                    vibrator.vibrate(VibrationEffect.createOneShot(500, VibrationEffect.DEFAULT_AMPLITUDE));
                } else {
                    //deprecated in API 26
                    vibrator.vibrate(500);
                }
                countPoweroff =0;

            }
            wasScreenOn = true;

        }else if(intent.getAction().equals(Intent.ACTION_USER_PRESENT)){




        }
    }

在主要活动中运行服务

startService(new Intent(getApplicationContext(), LockService.class));

我在主要活动中使用了基本的 Locationmanager 代码，该代码仅在活动打开时才有效。

Answer 1

您放入活动中的任何代码当然只会在活动运行时执行。如果您的位置管理器处于活动状态且活动未运行，则您无法获取位置信息。当司机关闭引擎并去午休时，您的公共汽车将不会移动到任何地方。在活动中做任何与 Ux 无关的事情都是糟糕的设计。我不知道您的实现细节，因此很难说更多。您应该在服务中实现位置管理器并使用 Callable 或 CompletableFuture 将结果发送到活动。