【发布时间】:2015-03-29 00:08:25
【问题描述】:
segue 运行,但应用程序因上述错误而崩溃。为什么我会收到此no segue with identifier 消息?我定义了segue标识符。
这里是 viewDidAppear 方法
- (void)viewDidAppear:(BOOL)animated
{
[self performSegueWithIdentifier:@"showAlerting" sender:self];
}
- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
{
if ([[segue identifier] isEqualToString:@"showAlerting"])
{
NSLog(@"Logging showAlerting");
}
}
我收到了这些日志消息
2015-03-28 20:04:33.025 xxxx[3684:741007] Logging showAlerting
2015-03-28 20:04:33.046 xxxx[3684:741007] xxxxxxxx,,
2015-03-28 20:04:33.111 xxxx[3684:741007] lat: xxx
2015-03-28 20:04:33.112 xxxx[3684:741007] lon: xxx
2015-03-28 20:04:33.798 xxxx[3684:741007] *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: 'Receiver (<ViewController: 0x17d38930>) has no segue with identifier 'showAlerting''
*** First throw call stack:
(0x2c1a15a7 0x39d87c77 0x2f9830df 0xebde7 0x2f6bb37b 0x2f6bb837 0x2f9701bb 0x2fd00e89 0x2f9726ff 0x2f7b5baf 0x2f7b5a4f 0x2f7b5525 0x2f6d9201 0x2f6d9117 0x2f0d363b 0x276187 0x279e9d 0x2c167891 0x2c165fb1 0x2c0b2b51 0x2c0b2963 0x335f11a9 0x2f704c91 0xea5f5 0x3a330aaf)
libc++abi.dylib: terminating with uncaught exception of type NSException
【问题讨论】:
-
您是否有多个 ViewController 实例?
-
我不知道,我有一个
Main.storyboard和LaunchScreen.xib是否会生成两个 ViewController 实例? -
您要使用的控制器的类是什么?在情节提要中检查其类。
-
源和目标都是类
ViewController -
好的,那是你的问题,因为第二个没有附加segue。您应该更改该控制器的类。
标签: ios segue uistoryboardsegue viewdidappear