如何在推送前关闭模型视图控制器？

Question

目前我的情况是这样的，

View Controller(VC1)  -->  Push Segue --> View Controller(VC2)
          |                                   ^ 
          | Model Segue                       |
          |                                   | Push Segue
          |-----> View Controller(VC3)  ------|         

现在在VC3 中，当我推入VC2 时，我想关闭VC3 视图控制器和 在VC2 后退按钮之后应该是VC1's 后视图控制器我想弹出VC3

我想要的是当我从 VC3 推 VC2 时我想删除 VC3，然后它应该出现 VC1

Check Example

我是这样做的，谁能帮帮我

视图控制器 (VC3)：

- (void)callWebservice {

   [self dismissViewControllerAnimated:YES completion:^{

         [self performSegueWithIdentifier:@"showVC2" sender:self];
   }];

}

提前致谢

Answer 1

我认为你可以这样实现：

• 当您在屏幕 3 时，您想要推送屏幕 2。您将关闭屏幕 3 并调用代理返回屏幕 1。
• 您将从 screen1 将视图推送到 screen2。

您可以查看我的演示以了解我的想法：Demo Pushview Swift

DemoPushViewObj

Answer 2

如果您使用 segue，我认为您正在寻找 https://stackoverflow.com/a/21415225/1320305，要手动执行此操作，请尝试以下操作：

你可以试试这个

 // locally store the navigation controller since
 // self.navigationController will be nil once we are popped
 UINavigationController *navController = self.navigationController;

 // retain ourselves so that the controller will still exist once it's popped off
 [[self retain] autorelease];

 // Pop this controller and replace with another
 [navController popViewControllerAnimated:NO];//not to see pop

 [navController pushViewController:aViewController animated:YES];
//to see push or u can change it to not to see.

或者试试这个

UIViewController *newVC = [[UIViewController alloc] init]; // Replace the current view controller 
NSMutableArray *viewControllers = [NSMutableArray arrayWithArray:[[self navigationController] viewControllers]];
[viewControllers removeLastObject]; 
[viewControllers addObject:newVC]; 
[[self navigationController] setViewControllers:viewControllers animated:YES];