【发布时间】:2015-03-26 12:31:10
【问题描述】:
我有一个 UITableViewController,我正在尝试使用此代码从 url 获取 JSON 数据,但出现错误。我该怎么办?
AFSecurityPolicy *securityPolicy = [[AFSecurityPolicy alloc] init];
[securityPolicy setAllowInvalidCertificates:YES];
NSString *urlPath = [NSString stringWithFormat:@"http://testurl.com/api/index.php"];
AFHTTPRequestOperationManager *manager = [AFHTTPRequestOperationManager manager];
NSDictionary *parameters = @{@"process":@"search_customer",@"page": @""};
manager.responseSerializer.acceptableContentTypes = [NSSet setWithObject:@"text/html"];
[manager setSecurityPolicy:securityPolicy];
manager.responseSerializer = [AFHTTPResponseSerializer serializer];
[manager POST:urlPath parameters:parameters success:^(AFHTTPRequestOperation *operation, id responseObject) {
NSString *string = [[NSString alloc] initWithData:responseObject encoding:NSUTF8StringEncoding];
NSData *jsonData = [NSData dataWithContentsOfFile:string];
NSError *error = nil;
NSDictionary *dataDictionary = [NSJSONSerialization JSONObjectWithData:jsonData options:0 error:&error];
self.customerCards = [NSMutableArray array];
NSArray *customersArray = [dataDictionary objectForKey:@"musteri_list"];
for (NSDictionary *customersDictionary in customersArray) {
ApiClass *customer = [ApiClass customersWithTitle:[customersDictionary objectForKey:@"adi"]];
customer.tel = [customersDictionary objectForKey:@"tel"];
[self.customerCards addObject:customer];
}
NSLog(@"GET: %@", string);
NSLog(@"POST: %@", parameters);
} failure:^(AFHTTPRequestOperation *operation, NSError *error) {
NSLog(@"Error: %@", error);
}];
这是错误块
2015-03-26 14:27:37.656 SaphiraCrm[13770:3881729] *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: 'data parameter is nil'
【问题讨论】:
-
你假设 [dataDictionary objectForKey:@"musteri_list"];存在。如果您没有有效的 dataDictionary,则该行下的所有代码都会导致崩溃。所以在开始使用循环条件之前验证字符串、jsonData、dataDictionary 等是否有效。
-
另外你为什么不使用
AFJSONResponseSerializer直接获取JSON。 -
尝试使用断点调试它并准确检查它崩溃的位置。
标签: ios objective-c json uitableview afnetworking