将数组添加到 NSDictionary 中的不同键

Question

我正在向具有不同键的 NSDictionary 添加一个数组。 这是抽象：

NSMutableDictionary *myDict = [[NSMutableDictionary alloc] init];   
    for (int i = 0; i < 3; i++) {
        [myArray removeAllObjects];      
        [myArray addObject:i];
        [myArray addObject:i];   
        [myArray addObject:i];   
        [myDict setObject:myArray forKey:[NSString stringWithFormat:@“%i”, i]];
         NSLog(@"%@", myDict);
    } 

这就是我得到的输出：

i = 1

“1” = ( “1”, “1”, “1”, “1” );

i = 2

“1” = ( “2”, “2”, “2”, “2” );

“2” = ( “2”, “2”, “2”, “2” );

i = 3

“1” = ( “3”, “3”, “3”, “3” );

“2” = ( “3”, “3”, “3”, “3” );

“3” = ( “3”, “3”, “3”, “3” );

但是如何获得呢？：

i = 3

“1” = ( “1”, “1”, “1”, “1” );

“2” = ( “2”, “2”, “2”, “2” );

“3” = ( “3”, “3”, “3”, “3” );

提前感谢您的帮助。

Answer 1

您不能一遍又一遍地重复使用同一个数组。这样做：

NSMutableDictionary *myDict = [[NSMutableDictionary alloc] init];   
for (int i = 0; i < 3; i++) {
    NSMutableArray *myArray = [NSMutableArray array];
    [myArray addObject:@(i)];
    [myArray addObject:@(i)];   
    [myArray addObject:@(i)];   
    [myDict setObject:myArray forKey:[NSString stringWithFormat:@"%i", i]];
     NSLog(@"%@", myDict);
} 

请注意，您不能将int 值直接添加到数组中。请注意，您需要将它们包装为 NSNumber 对象。

Answer 2

NSMutableDictionary *myDict = [[NSMutableDictionary alloc] init];
for (int i = 1; i < 4; i++) {
    NSMutableArray *myArray = [NSMutableArray arrayWithCapacity:3];
    [myArray addObject:[NSString stringWithFormat:@"%i", i]];
    [myArray addObject:[NSString stringWithFormat:@"%i", i]];
    [myArray addObject:[NSString stringWithFormat:@"%i", i]];
    [myDict setObject:myArray forKey:[NSString stringWithFormat:@"%i", i]];
    NSLog(@"%@", myDict);
}