【发布时间】：2020-11-04 17:28:36
【问题描述】：
我正在尝试使用xcodebuild CLI 来构建我的应用程序，其中包含“发布配置”(-c Release) 和 iOS 模拟器的目标 (-destination "platform: iOS Simulator")。但是，xcodebuild 似乎不支持这种行为，因为它的响应是：
$ xcodebuild -workspace Y.xcworkspace -scheme X -configuration Release -destination 'platform=iOS Simulator'
xcodebuild: error: Unable to find a destination matching the provided destination specifier:
{ platform:iOS Simulator }
Missing required device specifier option.
The device type “iOS Simulator” requires that either “name” or “id” be specified.
Please supply either “name” or “id”.
Available destinations for the "X" scheme:
{ platform:iOS Simulator, id:E01124DF-3E66-490B-BD28-351FF6CD3D1A, OS:14.1, name:iPad (8th generation) }
{ platform:iOS Simulator, id:40233395-556F-4A5B-A499-A238C4FA159A, OS:14.1, name:iPad Air (4th generation) }
{ platform:iOS Simulator, id:FE1018BD-4128-4E1F-9FE8-FEA4054DD8A8, OS:14.1, name:iPad Pro (9.7-inch) }
{ platform:iOS Simulator, id:88F79AD4-1F96-48B8-897B-D74DB4D6BBC2, OS:14.1, name:iPad Pro (11-inch) (2nd generation) }
{ platform:iOS Simulator, id:54BA4991-5C8D-41E4-9615-AEFDFAF167ED, OS:14.1, name:iPad Pro (12.9-inch) (4th generation) }
{ platform:iOS Simulator, id:2BEF87F9-5F1A-4339-B2C4-B9E634D03DB4, OS:14.1, name:iPhone 8 }
{ platform:iOS Simulator, id:E9CFA859-26B4-4009-A2FB-80161792FA30, OS:14.1, name:iPhone 8 Plus }
{ platform:iOS Simulator, id:DA1BE525-88B4-46F9-BE22-2EE2F46B669E, OS:14.1, name:iPhone 11 }
{ platform:iOS Simulator, id:5C658068-B26A-4265-9D49-D84084BFBB4F, OS:14.1, name:iPhone 11 Pro }
{ platform:iOS Simulator, id:455801A6-11F7-473B-97EB-FFE991C0CF48, OS:14.1, name:iPhone 11 Pro Max }
{ platform:iOS Simulator, id:7FC46741-BE28-4FA1-9921-6D341EAC5A36, OS:14.1, name:iPhone 12 }
{ platform:iOS Simulator, id:F5321E54-6500-4349-9175-C9715F3E230B, OS:14.1, name:iPhone 12 Pro }
{ platform:iOS Simulator, id:B3F46645-5380-4566-9070-DA25817B88D2, OS:14.1, name:iPhone 12 Pro Max }
{ platform:iOS Simulator, id:EBA39463-9D2E-40AB-B2E7-E802D8AE8680, OS:14.1, name:iPhone 12 mini }
{ platform:iOS Simulator, id:16F15877-230B-46FC-A36C-C984DFE12E66, OS:14.1, name:iPhone SE (2nd generation) }
{ platform:iOS Simulator, id:1588FB27-6FD2-4970-9D55-FF430006C766, OS:14.1, name:iPod touch (7th generation) }
Ineligible destinations for the "X" scheme:
{ platform:iOS, id:dvtdevice-DVTiPhonePlaceholder-iphoneos:placeholder, name:Any iOS Device }
{ platform:iOS Simulator, id:dvtdevice-DVTiOSDeviceSimulatorPlaceholder-iphonesimulator:placeholder, name:Any iOS Simulator Device }
{ platform:macOS, variant:Mac Catalyst, name:Any Mac }
TLDR：
-
为什么将 Any iOS Simulator Device 选项列为不合格？
-
有没有办法为模拟器创建发布风格的构建？
注意：我也尝试使用 -sdk iphonesimulator 选项而不是 -destination ...，但我的 iOS 应用程序包含一个 WatchKit 应用程序，当它尝试构建该依赖项时会混淆 xcode。
【问题讨论】：
-
“为什么将任何 iOS 模拟器设备选项列为不合格”因为它没有任何意义。没有任何 iOS 模拟器之类的东西。您为特定的模拟设备构建。
标签： ios iphone xcode xcodebuild