【发布时间】:2011-08-01 10:26:32
【问题描述】:
下面是读取名为 Example1.jpg 的图像的 r、g、b 值并在新的文本文件 out.txt 中显示所有值的代码。
但是如何读取文件夹内所有图片的 r,g,b 值呢?
int main(int argc, char** argv)
{
//while there are still images inside the folder,
//how to loop al images in a folder and read their r,g,b values//
//load the image in color
IplImage *img = cvLoadImage("Example.jpg",CV_LOAD_IMAGE_COLOR);
//set up pointer to access image data
uchar * data = (uchar*) img->imageData;
//get nchannels and step;
int nchannels = img->nChannels;
int step = img->widthStep;
//calculate r,g,b value
int b,g,r;
//display all pixel of the picture
int width = img->width;
int height= img->height;
int row,col;
//declare and open a output text file
ofstream outData;
outData.open("out.txt");
for (row=0; row<height; row++){
for(col=0; col<width; col++){
b = data[col*step + row*nchannels + 0];
g = data[col*step + row*nchannels + 1];
r = data[col*step + row*nchannels + 2];
outData<<r<<" "<<g<<" "<<b<<endl;
}
}
//wait user press key to exit
cvWaitKey(0);
//free memory
cvDestroyWindow("Skin");
cvReleaseImage(&img);
//press any key to continue
system("PAUSE");
}
【问题讨论】:
标签: c# c++ programming-languages opencv