我的辅音/元音替换有什么错误？

Question

所以我正在制作一个小程序。您输入一个字符串然后我的程序输出该字符串，除了a是辅音现在是“C”而元​​音是“V”。为什么当我输入时它输出错误“ Elicopter”或者其他词？

#include <iostream>
#include <string>
using namespace std;

int main()
{
const char con[]={'b','c','d','f','g','h','i','j','k','l','m','n','p','q','r','s','t','v','w','x','y','z','B','C','D','F','G','H','I','J','K','L','M','N','P','Q','R','S','T','V','W','X','Y','Z'};
const char vow[]={'a','e','i','o','u','A','E','I','O','U'};
const char car[]={'!','@','#','$','%','^','&','*','?','+','-','_','0','1','2','3','4','5','6','7','8','9'};
int scon=sizeof(con)/sizeof(con[0]);
int svow=sizeof(vow)/sizeof(vow[0]);
int scar=sizeof(car)/sizeof(car[0]);
string x;
int i,j;

getline(cin,x);

for(i=0;i<x.length();i++){
    if(x[i]==' '){
        cout<<" ";
    }

    else{

    for(j=0;j<scon;j++){
        if(x[i]==con[j]){
            cout<<"C";
            break;
        }
    }
    for(j=0;j<svow;j++){
        if(x[i]==vow[j]){
            cout<<"V";
            break;
        }
    }
    for(j=0;j<scar;j++){
        if(x[i]==car[j]){
            cout<<x[i];
            break;
        }
    }
}
}



    return 0;
}

对不起，我的代码一团糟。

Answer 1

除了@1201ProgramAlarm 已经指出的明显内容（'i' 在辅音列表中）之外，还有很多非常单一的代码——就像你用 C 编码的方式，而且 C 质量相当低那个（没有冒犯）。

虽然没有任何代码是完美的，但也许您可以从用实际 C++ 编写的相同（嗯，非常相似...）程序中受益。只是想知道您可以做什么。

#include <iostream>
#include <string>
#include <string_view>
#include <locale>

// "using namespace" is a habit that tends to get in the way
// once you start including headers from multiple namespaces,
// so while it has its place in quick one-shots, personally I
// got into the habit of fully qualifying.

int main()
{
    // This is, of course, very non-international, but I will
    // let this slide and not drag the ICU library into this...
    std::string_view const consonants { "bcdfghjklmnpqrstvwxyz" };
    std::string_view const vowels { "aeiou" };
    std::string input;

    // while instead of if allows you to make multiple lines of
    // input. <Ctrl>-D to end the program (<Ctrl>-Z <Enter> on
    // Windows).
    while ( getline( std::cin, input ) )
    {
        // Range-For eliminates the need for loop counters / iterators
        for ( auto const c : input )
        {
            if ( consonants.find( std::tolower( static_cast<unsigned char>( c ) ) ) != std::string::npos )
            {
                std::cout << 'C';
            }
            else if ( vowels.find( std::tolower( static_cast<unsigned char>( c ) ) ) != std::string::npos )
            {
                std::cout << 'V';
            }
            else if ( std::isprint( static_cast<unsigned char>( c ) ) )
            {
                // Not exactly the same as your list of digits
                // and punctuation, but similar, and showing the
                // use of character types. isprint() is also true
                // for ' '.
                std::cout << c;
            }
        }

        // std::endl ensures a flush of the write buffer
        std::cout << std::endl;
    }
}