带有文本和整数组件的 ShowMessage答案

【问题标题】：ShowMessage with text and integer components带有文本和整数组件的 ShowMessage
【发布时间】：2012-09-24 04:14:23
【问题描述】：

我无法显示由某些文本和整数组合而成的消息

这是我的代码：

int integerNumberOfImportantAppointments = calCalendar.getNumberOfImportantAppointments();

if (integerNumberOfImportantAppointments > 0)
{
    ShowMessage("You have " + integerNumberOfImportantAppointments + " important appointments. Do you wish to view them?");
}

我收到以下错误：E2085 无效的指针添加

我可以帮我解决这个问题吗？

谢谢

【问题讨论】：

标签： c++ string integer message

【解决方案1】：

您最好使用std::istringstream，而不是使用sprintf 或itoa（或类似的）：

int iNumberOfImportantAppointments = calCalendar.getNumberOfImportantAppointments();

if (iNumberOfImportantAppointments > 0)
{
    std::istringstream istr;
    istr << "You have " << iNumberOfImportantAppointments << " important appointments. Do you wish to view them?";
    ShowMessage(istr.str().c_str());
}

PS。描述性的变量/函数名称很好，但也有这样的太长名称。 :)

【讨论】：

【解决方案2】：

试试这个：

int integerNumberOfImportantAppointments = calCalendar.getNumberOfImportantAppointments();
if (integerNumberOfImportantAppointments > 0)
{
   // itoa is not standard (like any of this is)
   WCHAR strN[32];
   swprintf(strN, L"%d", integerNumberOfImportantAppointments);

   // not familiar with ShowMessage(), but I *think* this will work.
   ShowMessage("You have " + UnicodeString(strN) + " important appointments. Do you wish to view them?");
}

【讨论】：

【解决方案3】：

关于这个：

int integerNumberOfImportantAppointments = calCalendar.getNumberOfImportantAppointments();
char buffer[30];
if (integerNumberOfImportantAppointments > 0)
{
itoa (integerNumberOfImportantAppointments,buffer,10);
    ShowMessage("You have " + buffer + " important appointments. Do you wish to view them?");
}

【讨论】：

谢谢。我收到以下错误：E2193 Too little parameters in call to 'itoa(int,char *,int)' and E2034 Cannot convert 'string' to 'UnicodeString'