错误 C2064：术语不计算为采用 1 个参数的函数

Question

class Student {
    // ...
    bool Graduate() { return m_bGraduate; }
    // ...
};

class School {
    vector<Student*> m_vecStudents;

    void DelAndNullify(Student* &pStd);
    void Fun1();
};

void School::DelAndNullify(Student* &pStd)
{
    if ( (pStd != NULL) && (pStd->Graduate()) )
    {
        delete pStd;
        pStd = NULL;
    }
}

void School::Fun1()
{
    for_each(m_vecStudents.begin(), m_vecStudents.end(), mem_fun(&School::DelAndNullify));
}

错误 1 ​​错误 C2064：术语不计算为采用 1 个参数的函数 C:\Program Files\Microsoft Visual Studio 10.0\VC\include\algorithm 22 1 Simulation

为什么会出现这个错误？

---

更新

将Student 更改为pStd

---

更新 // 算法文件

template<class _InIt, class _Fn1> inline
_Fn1 _For_each(_InIt _First, _InIt _Last, _Fn1 _Func)
{
    // perform function for each element
    for (; _First != _Last; ++_First)
        _Func(*_First); // <<<<<<<< this line!
    return (_Func);
}

顺便说一句，如果我将DelAndNullify 定义为static，那么以下行将通过编译器

for_each(m_vecStudents.begin(), m_vecStudents.end(), ptr_fun(&School::DelAndNullify));

---

2012 年 5 月 9 日更新

#include <string>
#include <fstream>
#include <vector>
#include <algorithm>
#include <iterator>
#include <string>
#include <iostream>
#include <iomanip>
#include <functional>
#include <boost/bind.hpp>

class Student {
public:
    Student(int id, bool bGraduate) : m_iID(id), m_bGraduate(bGraduate) {}
    bool Graduate() const { return m_bGraduate; }
private:
    int  m_iID;
    bool m_bGraduate;
};

class School {
public:
    School(int numStudent)
    {
        for (int i=0; i<numStudent; ++i)
        {
            m_vecStudents.push_back(new Student(i+1, false));
        }
    }

    ~School() 
    {   
        // deallocate the allocated student resource to prevent memory leak!
    }

    void DelAndNullify(Student* &pStd);
    void Fun1();

private:
    std::vector<Student*> m_vecStudents;

};

void School::DelAndNullify(Student* &pStd)
{
    if ( (pStd != NULL) && (!pStd->Graduate()) )
    {
        delete pStd;
        pStd = NULL;
    }
}

void School::Fun1()
{   // http://stackoverflow.com/questions/6065041/error-c2064-term-does-not-evaluate-to-a-function-taking-1-arguments
    std::for_each(m_vecStudents.begin(), m_vecStudents.end(), std::bind1st(std::mem_fun(&School::DelAndNullify), this));
    //boost::bind(&School::DelAndNullify, this, _1);
}

int main(int /*argc*/, char* /*argv*/[])
{
    School school(10);
    school.Fun1();
    return 0;
}

错误 1 ​​错误 C2535: 'void std::binder1st<_fn2>::operator ()(Student *&) const' : 成员函数已定义或声明 c:\Program Files\Microsoft Visual Studio 10.0\VC\include\xfunctional 299

Answer 1

std::mem_fun(&School::DelAndNullify) 返回一个二元仿函数，它采用 School* 和 Student*，但 std::for_each 期望一元仿函数仅采用 Student*。请改用Boost.Bind：

std::for_each(
    m_vecStudents.begin(),
    m_vecStudents.end(),
    boost::bind(&School::DelAndNullify, this, _1)
);

如果您有足够新的编译器，那么您可以使用std::bind 或std::tr1::bind 代替Boost 库；或者，如果您使用的是支持 C++11 lambda 的编译器，那么您可以执行以下操作，而不是使用任何 bind：

std::for_each(
    m_vecStudents.begin(),
    m_vecStudents.end(),
    [this](Student*& s){ DelAndNullify(s); }
);

Answer 2

看起来mem_fun 把你的成员函数变成了一个“静态”函数，它把一个对象作为它的第一个参数，比如：

static void DelAndNullfify(Student *pStudent);

但是你已经在 pre-mem_fun'd 函数中有一个参数，所以你最终得到：

static void DelAndNullfify(School *pSchool, Student* &prStudent);

一个参数太多了。

Answer 3

这个

mem_fun(&School::DelAndNullify)

返回一个二进制函数，期望School*和Student*。

使用

bind1st(mem_fun(&School::DelAndNullify), this)

改为。