【发布时间】:2017-08-09 06:41:24
【问题描述】:
我是 openCV 的新手。
我刚刚从 Github 下载了 openCV 的源码,并安装在桌面(Mac OS)上。
现在我需要将二进制文件转换为图像文件。这是代码:
// The program is first to convert the image to the binary file then convert the binary file back to the image
#include <iostream>
#include </Users/Me/Desktop/opencv-master/include/opencv2/opencv.hpp>
#include </Users/Me/Desktop/opencv-master/modules/highgui/include/opencv2/highgui.hpp>
const std::string filename = "test.dat";
const std::string picname = "pano_b.jpg";
int main(int argc, char **argv)
{
std::ofstream outfile;
outfile.open(filename.c_str(), std::ios::binary);
if (!outfile)
{
std::cerr << "failed to open the file : " << filename << std::endl;
return -1;
}
cv::Mat srcImg = cv::imread(picname);
if (srcImg.empty())
{
std::cerr << "failed to open the file : " << picname << std::endl;
return -1;
}
for (int r = 0; r < srcImg.rows; r++)
outfile.write(reinterpret_cast<const char*>(srcImg.ptr(r)), srcImg.cols*srcImg.elemSize());
std::cout << "write to file ok!" << std::endl;
///// Here the file test.dat is generated. It looks like this:
///// 0069 a800 6caa 0074 af0c 80b9 2096 ca2a
///// 9fd2 1c8d bf03 71a1 0773 a300 6295 0064
///// 9907 73a9 0070 a900 6da8 0480 bc18 95d2
///// ...
//////// Now I want to convert test.dat into an image file
cv::Mat img = cv::imread(filename.c_str(), cv::IMREAD_ANYCOLOR);
cv::imshow("img", img);
cv::waitKey();
return 0;
}
但是我收到如下错误:
架构 x86_64 的未定义符号:“cv::imshow(cv::String const&, cv::_InputArray const&)",引用自: bbb-bb77f0.o ld 中的 _main:未找到架构 x86_64 clang 的符号:错误:链接器命令失败,退出代码为 1(使用 -v 到 见调用)
正如我所说,我在桌面上安装了 openCV,这是我的编译方式:
g++ test.cpp /Users/Me/Desktop/opencv-master/build/lib/libopencv_core.dylib /Users/Me/Desktop/opencv-master/build/lib/libopencv_imgproc.dylib /Users/Me/Desktop/opencv-master/build/lib/libopencv_imgcodecs.dylib
我应该怎么做才能解决这个链接错误?
【问题讨论】:
-
要使用 imread,您需要文件中的图像标题。如果您想手动读取二进制文件并从中构建图像,您必须知道原始数据的宽度、高度和像素类型。
-
@Micka 你能给我举个例子吗?