C++ 调试断言失败。向量下标超出范围

Question

我一直在寻找解决方案，我似乎正在修复他们的所有问题，但我的仍然无法正常工作。

以下代码显示来自名为 Creature 的类的向量，对向量进行排序，然后显示排序后的向量。

    // displaying the unsorted vector
for (int i = 0; i < MAX_NO_CREATURES; i++)
{
    if (creatures[i].getAlive() != 0) // checking to see if a creature exists
    {
        for (unsigned int j = 0; j < creatures[i].getAvaFood().size(); j++)
        {
            cout << creatures[i].getAvaFood()[j] << " ";
        }
    }
}

//sorting the vector
for (int i = 0; i < MAX_NO_CREATURES; i++) 
{
    if (creatures[i].getAlive() != 0) // checking to see if a creature exists
    {
        creatures[i].bubbleSort(creatures[i].getAvaFood()); // calling a sorting function from creatures[i] passing in the relevant vector (its own.. wait what?)
    }
}

cout << endl;

// displaying the sorted vector
for (int i = 0; i < MAX_NO_CREATURES; i++)
{
    if (creatures[i].getAlive() != 0) // checking to see if a creature exists
    {
        for (unsigned int x = 0; x < creatures[i].getAvaFood().size(); x++)
        {
            cout << creatures[i].getAvaFood()[x] << " ";
        }
    }
}

当我在错误窗口上单击重试时，Visual Basic 将我带到生物类中的这一行。特别是 IF 语句。

void Creature::bubbleSort(vector<int> &v)
{
    bool swapped = true;
    int temp;
    while (swapped)
    {
        swapped = false;
        for (unsigned int i = 0; i < v.size(); i++)
        {
            if (v[i] > v[i + 1])
            {
                temp = v[i];
                v[i] = v[i + 1];
                v[i + 1] = temp;
                swapped = true;
            }
        }
    }
}

Answer 1

    for (unsigned int i = 0; i < v.size(); i++)
    {
        if (v[i] > v[i + 1])

for 允许 i 为所有值 [0, v.size) 这意味着您将测试无效的 v[v.size]。

将你的 for 循环更改为

    for (unsigned int i = 0; i < v.size() - 1; i++)

您需要添加一个检查以确保 v.size() 不为零。