我在此处发布的程序从一个或多个按您需要格式化的字符串中提取参数。函数extract 提取字符串(您指定的格式)中包含的所有参数,并将它们的名称和值插入到结构(struct sParms)数组中。
您可以将程序编译为提取并在系统提示符下执行它:
用户名:./extract "date =20170422,line =10,index =3,field
=partType,lock =productCode1,bookmark=2/19/56,"
输出如下:
[date]=[20170422]
[line]=[10]
[index]=[3]
[field]=[partType]
[lock]=[productCode1]
[bookmark]=[2/19/56]
您可以使用多个字符串执行程序:
用户名:./extract "date =20170422,line =10,index =3,field
=partType,lock =productCode1,bookmark=2/19/56," "yes=1, no=0"
输出如下:
[date]=[20170422]
[line]=[10]
[index]=[3]
[field]=[partType]
[lock]=[productCode1]
[bookmark]=[2/19/56]
[yes]=[1]
[no]=[0]
下面一行是代码:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <libgen.h>
//Parameters: date =20170422,line =10,index =3,field =partType,lock =productCode1,bookmark=2/19/56,
#define SEPARATOR ','
#define ASSIGNEMENT '='
typedef struct sParms {
char * fieldName;
char * fieldValue;
} tsParms;
int loadString(char *to, const char *from);
int extract(tsParms **oparms, const char *inb);
// Retrieve buffer length
int loadString(char *to, const char *from)
{
int len=0;
while(*from<=32 && *from!=SEPARATOR && *from!=ASSIGNEMENT)
from++;
// Get the string value
while(*from>32 && *from!=SEPARATOR && *from!=ASSIGNEMENT) {
*(to+len++)=*from;
++from;
}
*(to+len++)=0;
return len;
}
int extract(tsParms ** oparms, const char *inb)
{
int cnt=0,j;
const char * end, *equ, *start;
char * buff;
tsParms * parms;
if (inb == NULL || strlen(inb) == 0 || oparms == NULL)
return 0;
// It counts the number of parms
end=strchr(inb,ASSIGNEMENT);
while(end) {
cnt++;
end=strchr(end+1,ASSIGNEMENT);
}
if (!cnt)
return 0;
/* Doing some considerations we may assume that the memory to use to store
* fields name and values is the same of the input string (inb)
*
* The space to store the pointers is cnt * sizeof(tsParms *).
*/
j=cnt * sizeof(tsParms) + strlen(inb);
parms = malloc(j+1);
memset(parms,0,j+1);
buff = (char *)(parms+cnt); // The memory area where we can save data!
start=inb;end=start;cnt=0;
do {
end=strchr(start,SEPARATOR);
equ=strchr(start,ASSIGNEMENT);
if (equ) {
//Get the field name
parms[cnt].fieldName=buff;
buff+=loadString(buff,start);
//Get the field value
start=equ+1;
parms[cnt].fieldValue=buff;
buff+=loadString(buff,start);
cnt++;
}
if (end)
start=end+1;
} while(end);
*oparms = parms;
return cnt;
}
int main(int argc, char *argv[])
{
int i,j,cnt=0,retval=0;
tsParms * parms=NULL;
if (argc<2) {
printf("Usage: %s \"string-1\" [\"string-2\" ...\"string-n\"]\n",basename(argv[0]));
return 1;
}
for(i=1; i<argc; i++) {
cnt=extract(&parms, argv[i]);
if (cnt!=0 && parms!=NULL) {
for(j=0;j<cnt;j++) {
printf("[%s]=[%s]\n",parms[j].fieldName,parms[j].fieldValue);
}
puts("");
free((void *)parms);
} else {
retval=1;
break;
}
}
return retval;
}